lychnobity
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Thanks in advance
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for 1) Use demoivre's on z^n+conj. z^n where z=cis@Thanks in advance
there maybe a problem with your solution for 1)...
there may be some issues with taking the logarithm of the presumably complex number, but then thats all uni math crap
oo yes, there isthere maybe a problem with your solution for 1)
Ok nw. btw, 1) has been solved by Gurmies.oo yes, there is
thanks for that (you and gurmies)
Not quite - I cheatedOk nw. btw, 1) has been solved by Gurmies.