a simple complex locus question (1 Viewer)

[Mainoyi]

For the locus of z:
arg z = pie/3
|z| less/equal to 2

should the origine be included?

 

[untouchablecuz]

no

arg(0+0i) is undefined

 

[cutemouse]

no

arg(0+0i) is undefined

No ==> Indeterminable. Undefined is something like 2/0...

 

[moshi.bum]

Thanks for that. ^^

 

[untouchablecuz]

No ==> Indeterminable. Undefined is something like 2/0...

meh, semantics

"Note that the argument of zero is not undefined, [that is, it is undefined]" - 4 Unit Cambridge Mathematics Pg 34

 

[cutemouse]

There are four cases of indeterminable. They are:

0/0 , infinity*0 , infinity - infinity, infinity*0


There is a difference between undefined and indetermineable.

 

[gurmies]

For an argument to be defined, there needs to be a distance between one point on the argand plane and the origin. Since there is no distance between the origin and itself (lol) a line can't be drawn. Therefore, there is no angle formed.

 

[untouchablecuz]

There are four cases of indeterminable. They are:

0/0 , infinity*0 , infinity - infinity, infinity*0

There is a difference between undefined and indetermineable.

on a serious note: where in those 4 cases does arg(0) appear

 

[cutemouse]

on a serious note: where in those 4 cases does arg(0) appear

Umm... you do know that arg(a+ib) = tan^-1(b/a) right?

 

[cutemouse]

Therefore, there is no angle formed.

So it is not undefined. If it's undefined that means the angle=infinity, which is clearly not the case. So it's indeterminable.

 

[study-freak]

So it is not undefined. If it's undefined that means the angle=infinity, which is clearly not the case. So it's indeterminable.

If it's defined, what is its definition lol?

 

[untouchablecuz]

Umm... you do know that arg(a+ib) = tan^-1(b/a) right?

oh ok

 

[shaon0]

So it is not undefined. If it's undefined that means the angle=infinity, which is clearly not the case. So it's indeterminable.

dude, who cares.