No it has to be 1:2 as they asked for a side of the smaller triangle in ratio to the larger triangle therefore they cant be even...but rather the side of the larger triangle is double the smaller triangle.Can anyone confirm me please?
No it has to be 1:2 as they asked for a side of the smaller triangle in ratio to the larger triangle therefore they cant be even...but rather the side of the larger triangle is double the smaller triangle.Can anyone confirm me please?
ohhh crap yeah i realise now thanksNo it has to be 1:2 as they asked for a side of the smaller triangle in ratio to the larger triangle therefore they cant be even...but rather the side of the larger triangle is double the smaller triangle.
The pipe costs $2600/km under the water, and $1000/km on land. The line PS is underwater.why X2600 for 9bii?
if we times 1000 from R to S, Q to S
then isn't we should times 1000 from P to s as well?
When I first looked at it I had to carefully think about underwater and on the shore, the diagram was pretty shit tbh.The pipe costs $2600/km under the water, and $1000/km on land. The line PS is underwater.
Where did you lose them so far?Edited. This team-work is quite depressing. My mark is down to 115 now
2 lost in 3b, 2 lost in 4c and 1 in 5b so far. I cannot remember the signs I used in 8a, hopefully the right ones. It is only a 1 mark question though, so hopefully they 'round up'.Where did you lose them so far?
Did you put the greater and less than or equal to in the exam or just less than / greater than in that one i posted about?
Latex is not working.thanks OP, you = cool
Does anyone have a proof for 10 c) ii)?
I'm not sure my answer was sufficient...
still, if it is, 118 XDXD
I haveQuestion 4) part (a)
a= 2.3
r= 1.9
When you limiting sum = a/1-r
the answer is
- 4/3.
um, r was 0.9 not 1.9. you can't have a negative limiting sum. the answer is 12Question 4) part (a)
a= 2.3
r= 1.9
When you limiting sum = a/1-r
the answer is
-4/3