+1never used the third derivative test, never bothered to, never will.
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+1never used the third derivative test, never bothered to, never will.
+1Why is a HSC 2011'er thinking they know more than an engineering student?
I don't think there's a purpose, it's just another term for a feature you need to be aware of.+1
and back to the topic..
at first i got confused as well by these 2 things...
horizontal pt of inflexion is when y' = 0, y" = 0
when the inflexion pt is at the stationary pt, it is a horizontal pt of inflexion..
that how i remember it. :S
but can anyone tell me whats the purpose of the "horizontal" point of inflexion please?
thanks
y' = dx/dy or the 1st derivative.What does y'=0 and y''=0 mean. Isn't that referring to how u find inflection and stationary points? u let y' and y'' equal 0? What does it have to do with horizontal pt of inflexion?
so does that mean, when the x value is subbed in y' and y'', y' and y'' both =0?I don't think there's a purpose, it's just another term for a feature you need to be aware of.
y' = dx/dy or the 1st derivative.
y'' = dx^2/d^2y or the 2nd derivative,
Yes, it's refering to how you find points of inflection and stationary points, which you do by letting y' = 0 for stat pts and y'' = 0 for POIs (of course you need to prove concavity change too).
They have to do with a Horizontal POI because you need to find horizontal POIs by showing that they both satisfy the requirements of y' = 0 and y'' = 0![]()
If it's a Horizontal POI, yesso does that mean, when the x value is subbed in y' and y'', y' and y'' both =0?
I don't. I just knew that this engineer was wrong in this particular instance.Why is a HSC 2011'er thinking they know more than an engineering student?