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Conjugate acid-base equations (1 Viewer)

learner64

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Hello everyone

I just have a question regarding conjugate acid-base equations in general.

Consider the equation below:

H<SUB>2</SUB>SO<SUB>4</SUB> + H<SUB>2</SUB>O
HSO<SUB>4</SUB><SUP>-</SUP> + H<SUB>3</SUB>O<SUP>+ </SUP>

<SUP></SUP>
<SUP>For the equation above, would the conjugative acid be just </SUP>H<SUB>2</SUB>SO<SUB>4</SUB><SUP> and the base </SUP>HSO<SUB>4</SUB><SUP>-</SUP> <SUP>. </SUP>
<SUP></SUP>
<SUP>Or, would there be another pair of conjugative acid and base (i.e. </SUP>H<SUB>3</SUB>O<SUP>+ and </SUP>H<SUB>2</SUB>O<SUP>) together with the first pair?</SUP>
<SUP></SUP>
<SUP>Thanks</SUP><!--mstheme-->
 

adomad

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and are the acid and conjuagte base pair
and is the base and conjugate acid pair
 

learner64

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and are the acid and conjuagte base pair
and is the base and conjugate acid pair

thanks very much for that.. but why is the base and conjugate acid written first sometimes, then followed by acid and conjugate base?
 

iRuler

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whats a conjugate and base stuff??
In a nutshell its just removing 1 Hydrogen from an acid to make a negative ion for a conjugate base, and for conjugate acid, adding 1 H, i cant really explain it.

The following is a perfect example.

and are the acid and conjuagte base pair
and is the base and conjugate acid pair
 

h3ll h0und

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In a nutshell its just removing 1 Hydrogen from an acid to make a negative ion for a conjugate base, and for conjugate acid, adding 1 H, i cant really explain it.

The following is a perfect example.
*proton = hydrogen which has lost an electron.
 

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