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[ombuds]

A ball is thrown vertically upwards at 16ms^-1. What is the velocity after 2 seconds
(acceleration is 9.8 m/s/s)

Can someone please show working.

Thanks in advance

 

[s2 SEductive]

A ball is thrown vertically upwards at 16ms^-1. What is the velocity after 2 seconds
(acceleration is 9.8 m/s/s)

Can someone please show working.

Thanks in advance

I think u use

v = u + at

u(initial velocity) = 16 m/s
a = -9.8 m/s/s (works against gravity and retards)
t = 2 s

v = 16 + -9.8(2)

v= -3.6 m/s

 

[ohexploitable]

I haven't done this topic yet but using Year 10 Science...

v = u + at
v = 16 - 9.8*2
v = -3.6 ms^-1
v = 3.6 ms^-1, downwards

 

[ohexploitable]

I think u use

v = u + at

u(initial velocity) = 16 m/s
a = 9.8 m/s/s
t = 2 s

v = 16 + 9.8(2)

v= 35.6 m/s

If it's not right

Im sorry ><

Umm... so if you throw something up it accelerates and gravity pushes it up?

lol... gravity is working against the object, so the acceleration (deceleration) is -9.8ms^-1

 

[s2 SEductive]

Umm... so if you throw something up it accelerates and gravity pushes it up?

lol... gravity is working against the object, so the acceleration (deceleration) is -9.8ms^-1

LOL yeah Know
it's meant to retard Haha
yeah

just was about to edit it
but u wrote it soo yep it's fine

 

[hscishard]

A ball is thrown vertically upwards at 16ms^-1. What is the velocity after 2 seconds
(acceleration is 9.8 m/s/s)

Can someone please show working.

Thanks in advance

That confuses me. Is that the average acceleration?
I don't think the question will be exactly written as that.

Sorry, just saying.

 

[ombuds]

And is the displacement after 2 seconds 51.6m?

 

[s2 SEductive]

That confuses me. Is that the average acceleration?
I don't think the question will be exactly written as that.

Sorry, just saying.

constant acceleration of gravity
He probably wrote the first part , then instead of writing , The ball accelerates at (constant) 9.8 m/s/s towards blah blah blah . He just put it in brackets

 

[s2 SEductive]

And is the displacement after 2 seconds 51.6m?

You did + 9.8

the formula is r = ut = 1/2at^2

r = 16 x 2 + 1/2 x - 9.8 x 2^2

r = 12.4 m

 

[hscishard]

And is the displacement after 2 seconds 51.6m?

What how can that be, it was only two seconds.
It was going at a max of 16m/s

 

[ohexploitable]

That confuses me. Is that the average acceleration?
I don't think the question will be exactly written as that.

Sorry, just saying.

lol... gravity is constant... it doesn't change...

 

[ohexploitable]

Can't wait to do this topic... seems so math-like

 

[s2 SEductive]

Can't wait to do this topic... seems so math-like

Lol i'v done this topic first
it's A lot of maths
trust me , many formulas
but you'll like it
I'm used to it now


your pretty smart , knowing that your using year 10 knowledge

 

[hscishard]

No i was thinking that at 2 seconds, it is accerlerating at 9.8m/s

 

[ohexploitable]

No i was thinking that at 2 seconds, it is accerlerating at 9.8m/s

Yep, it's always accelerating at -9.8ms^-2.

 

[hscishard]

Yep, it's always accelerating at -9.8ms^-1.

No! I meant the ball was going +9.8m/s.

 

[s2 SEductive]

Yep, it's always accelerating at -9.8ms^-1.

the ball accelerates vertically upwards to the air lOL at 9.8 m/s/s

 

[ombuds]

You did + 9.8

the formula is r = ut = 1/2at^2

r = 16 x 2 + 1/2 x - 9.8 x 2^2

r = 12.4 m

I see where i tripped up.

Thanks so much..

 

[s2 SEductive]

I see where i tripped up.

Thanks so much..

No problem

 

[hscishard]

the ball accelerates vertically upwards to the air lOL at 9.8 m/s/s

WHAT? Instantaneously or...?

Time to consult my textbook

Omg I can't believe you did this topic already. We do it in term 3 (most likely not going to finish)