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Calculus - Derivatives (1 Viewer)

SpiralFlex

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Using the quotient rule, I think you mean this:











I shall check my algebra. What does answers say?
 
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hscishard

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with respect to x f'(x)
Well that's fucked..? df(x) / xf'(x) looks pretty hard..
If you mean with respect to x, then that's also fucked because you need an equation with r in terms of x
If you meant differentiate with respect to r, then try this:
f(r)= [(r-6)^3 +1 / (r-6)^3 + 1] -[2/(r-6)^3+1]
= 1 -2/(r-6)^3+1
Then use chain rule
 

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