Infinite Roots. (2 Viewers)

[Fus Ro Dah]

 

[barbernator]

where do you get all these questions from!? i want one

 

[Fus Ro Dah]

where do you get all these questions from!? i want one

Secretz

If you want one, try the one I gave above!

 

[barbernator]

carrot

If you want one, try the one I gave above!

sounds right!

 

[barbernator]

abc,4,4,2. there may be others...

 

[barbernator]

was expecting tips on how to sex infinite

strong english/10

 

[Fus Ro Dah]

abc,4,4,2. there may be others...

Yep there are more... in fact it's an inequality.

 

[barbernator]

my sol isnt an inequality, but when b=a^2/4 and when c=a/2, the function will have infinite roots.

therefore, for b>0, all real a, and all real c, the function CAN have unlimited roots. again, no idea if it is correct.

 

[barbernator]

btw fus, what is the actual answer to this?

 

[Carrotsticks]

c > 0 and a = -2c and b = c.

 

[Fus Ro Dah]

btw fus, what is the actual answer to this?

This.

c > 0 and a = -2c and b = c.

 

[someth1ng]

What the fuck? How the fuck do you do this?

 

[Carrotsticks]

What the fuck? How the fuck do you do this?

Think... what types of functions have infinite roots?

 

[someth1ng]

Think... what types of functions have infinite roots?

I swear I havent encountered infinite roots...or sinx? cosx?

 

[barbernator]

oh shit i see now lol. Just make the brackets a pertect square and factorise to cancel to 0

 

[Carrotsticks]

I swear I havent encountered infinite roots...or sinx? cosx?

Indeed periodic functions like those (not all though of course). Any others?

 

[someth1ng]

y=0 for infinite roots...RIGHT!

 

[barbernator]

when i did it originally, i differentiated and found the values of a and b when to make the derivative have a value of 0. and then i subbed into the initial function to find c. why did this not work?

 

[Bored_of_HSC]

when i did it originally, i differentiated and found the values of a and b when to make the derivative have a value of 0. and then i subbed into the initial function to find c. why did this not work?

Isn't that assuming the root is at a SP?

 

[barbernator]

Isn't that assuming the root is at a SP?

the x values cancelled, so there were no variable terms. So I just had a relation between a and b....

NVM fml, I neglected the denominator fack!