I remember that question,
It said something about which one would cause the greatest pH change if one of the following was added to HCl
I was tossing between diluting it with water and adding NaOH ...
Case with diluting it with water:
1L of dilute HCl: 0.001M = 0.001mol.L
-1
pH = -log
10(0.001) = 2
Add 1L of water:
c = n/v = 0.001/(1+1) = 0.0005mol.L
-1
Adding 1L of 1M NaOH:
1M = 1mol.L-1
Therefore, 1mol of NaOH.
pH = 14 - (-log10(1)) = 14 - 0 = 14
Adding this to HCl:
HCl(aq) + NaOH(aq) --> H2O + NaCl(aq)
Limiting agent is HCl.
Therefore NaOH remaining at the end is:
1mol - 0.001mol = 0.999moles of NaOH and 0 moles of HCl
Everything else is neutral.
Therefore, concentration is:
c = n/v = 0.999mol/2L = 0.4995M
pH = 14 - (-log[0.4995]) = 13.698… = 13.7
Therefore, adding NaOH brings the greatest change here.