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Please carrotsticks or someone, help with final maths problem (1 Viewer)

jackerino

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Ive solved all 40+ questions of my maths project, ONE LEFT, which I cannot do. Plz help

There is a triangle ABC, right angled. with the right angle at B. Extending AB to point D, and reflecting AC on AB, then extending it to point E due east of D, two similar triangles are formed. Angle ABC and angle ADE are 90 degrees, and a line connects E to C. The point F is the intersection of BD and EC.
ALso, AB equals (a) units, and the ratio of similarity is AB:AD=k:l

i)Prove triangle FBE is similar to triangle FDE
ii)Find the ratio of lengths BF to FD.
iii) Show that FD=(al(l-k))/k(l+k)
iv)Given that AB:AD=2:3, and FD is an integer, find the possible values of a.


Please help me guys LAST QUESTION!!!!
 
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jackerino

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SOMEBODY!!! PLEASE!!! I WONT BUG U ANYMORE!! last queston LITERALLY lolz.
 

jackerino

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omg pleeaaasssseee PLEASE PLEASE PLEASE PLEASE help me guys! PLEASE!! I figured out up to part iii), showing what FD is. I have FD=(al(l-k))/k, and I dont know how to transform the k into k(l+k). So if someone could help it would be AWESOME! aand if not that question, perhaps this:
In how many ways can a mixed doubles tennis match be made out of 6 married couples if no husband and wife are to play in the same match?


OMG OMG OMG OMG PLEAAASE HELP MEEEEEEEEEEEEEEEEEEEEEEE!!!
 

Carrotsticks

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Jeez, calm down. I'll write up a solution for you now.

Give me a few moments =)

Hold on, the point F wasn't defined...
 
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jamesischool

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i'd try to do it for you but i'm feeling really lazy. also aren't you in year 10 according to your hsc date?
 

jackerino

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i'd try to do it for you but i'm feeling really lazy. also aren't you in year 10 according to your hsc date?
Yes im in yr 10, I just sit in on extra classes with yr 12's LOL. They got a maths assignment thing with 40 something questions, and teacher changed a few of them and gave an altered version for me to do.
 

Sy123

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So people are doing your math assignment for you?
 

Sy123

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Ok, I guess I can help then. I will post a solution within the next hour or so.
 

Sy123

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Hang on the explanation of the diagram does not make sense, please post a diagram of the question.
 

jackerino

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Scanner not working sorry. Basically
Right angled triangle ABC, A is north pointing, B is right angle, C is west pointing. Now extend AB to a point D. then Reflect AC on the line AB, and extend it to a point E, due east of D. Join D with E. Now you have two similar triangles. Also, a line connects C with E, and this line intersects BD at point F.
 

Carrotsticks

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You typed to prove FBE is similar to FDE. Did you mean to prove FBC is similar to FDE?
 

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