Projectile Question (1 Viewer)

[Beaconite]

parts ii) and iii)

 

[Beaconite]

anyone?

 

[Sy123]

Answers:

Part ii



Part iii

 

[Beaconite]

How is x (aircraft) = Ut + k?

isn't it just Ut?

 

[Sy123]

If we are taking origin as (0,0) and that t=0 when projectile is fired, when t=0, the position of the aircraft is at B, not at A, so we need to find AB as well if that makes sense, its like integrating
And then finding +C (or k)

 

[Beaconite]

If we are taking origin as (0,0) and that t=0 when projectile is fired, when t=0, the position of the aircraft is at B, not at A, so we need to find AB as well if that makes sense, its like integrating
And then finding +C (or k)

how k=AB ? :S

 

[Sy123]

Using the triangle formed using alternate angles on the angle of the projection, its in my working out

 

[Beaconite]

so v=dx/dt=1/x

we differetiate it again , we get a=-1/x^2
we sub x=0.5 to find a right?

 

[Sy123]

No, since we know that if v is in terms of x



So what you do is, you manipulate v=1/x, into that form above, then sub in x=0.5

 

[RishBonjour]

View attachment 26245

so v=dx/dt=1/x

we differetiate it again , we get a=-1/x^2
we sub x=0.5 to find a right?

You do that when v is in terms of t. because, dv/dt is acceleration. not dv/dx. You use what sy123 used above.

Pay attention to your working and understand every step of it, or you will find it difficult to knock of "hard" questions