Limits question -a challenge (2 Viewers)

[HeroicPandas]

NO L HOPITAL RULE WHATEVER ITS CALLED, wolfram alpha used it...]

Can anyone look at my method to see if it is right, if there is another method, please post it up

My Method:









I will have to work slowly for the first limit just in-case there is confusion





NOW THIS IS THE PART... I reciprocated thingy under the limit






I would to know if there is another method

 

[Shadowdude]

just skimming

but why don't you make the change of variable u = 1/x and let u go to 0 instead


that should work.. i think. maybe. probably.

 

[HeroicPandas]

just skimming

but why don't you make the change of variable u = 1/x and let u go to 0 instead


that should work.. i think. maybe. probably.

My teacher did that, but does my method work?

 

[Shadowdude]

You pretty much did the u-substitution method... without the u.

But it looks really suss with the 1/infinity

 

[pokka]

My teacher did that, but does my method work?

It's basically the same method, it's just let's you recognise the limit easily by changing the variable. So yes I think your method works.

 

[SpiralFlex]

Yes it's valid. If both of the following limits exist:





Then the following is true.



So that's fine.

 

[oh well]

Yes it's valid. If both of the following limits exist:





Then the following is true.



So that's fine.

Isn't that L'Hopital's Rule?

 

[Shadowdude]

Isn't that L'Hopital's Rule?

No, L'Hopital has stuff to do with derivatives.

Not school stuff so I'll leave it to you to search for yourself.

 

[oh well]

NO L HOSPITAL RULE WHATEVER ITS CALLED, wolfram alpha used it...]

Can anyone look at my method to see if it is right, if there is another method, please post it up

My Method:









I will have to work slowly for the first limit just in-case there is confusion





NOW THIS IS THE PART... I reciprocated thingy under the limit






I would to know if there is another method

It's L'Hopital, not HOSPITAL LMAO

 

[SpiralFlex]

Isn't that L'Hospital's Rule?

No. L'Hopital's rule is different.





Edit: Sorry I forgot this was 3U. Never mind.

 

[HeroicPandas]

Yes it's valid. If both of the following limits exist:





Then the following is true.



So that's fine.

ok thank you

 

[seanieg89]

It's L'Hopital, not HOSPITAL LMAO

There are multiple spellings.

 

[Carrotsticks]