integration help. (1 Viewer)
- Thread starter Verify
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Kurosaki
True Fail Kid
Is the answer 1/16? thats what i got just then, not sure if accurate tho
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The answer is 3/4
Kurosaki
True Fail Kid
Lol fack it is 3/4 ( forgot to multiply both sides . brb latexing
. brb latexingKurosaki
True Fail Kid
Ok Verify so when x=0 and x=2 we know that the curve will have a y-value of zero at that point. thus those are the limits/whatever u call it u put onto the integrate symbol.
^2 dx=\int_{0}^{2}kx(4-4x+x^2)dx=\int_{0}^{2}4kx -4kx^2 +kx^3 dx=1 )
From there it is simple integration and then u sub in x=2 and x=0. I think this should be right anyways...
From there it is simple integration and then u sub in x=2 and x=0
. I think this should be right anyways...
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That's right - but leave the k outside; much easier.Ok Verify so when x=0 and x=2 we know that the curve will have a y-value of zero at that point. thus those are the limits/whatever u call it u put onto the integrate symbol.
From there it is simple integration and then u sub in x=2 and x=0