Differentiation of LOG FUNCTIONS (1 Viewer)

darlking · May 17, 2013

Hey, how do we dy/dx

a) 3^x
b) 2^3x-4

HeroicPandas · May 17, 2013

darlking said:
Hey, how do we dy/dx

a) 3^x
b) 2^3x-4

Use this:

$a = e^{ln(a)}$

Then use:

$\frac{d(e^{f(x)})}{dx} = f'(x)e^{f(x)} \\ \\ $Note: f(x) must be a linear function$

darlking · May 17, 2013

Please break it down for me

HeroicPandas · May 17, 2013

HeroicPandas said:
Use this:

$a = e^{ln(a)}$

Then use:

$\frac{d(e^{f(x)})}{dx} = f'(x)e^{f(x)} \\ \\ $Note: f(x) must be a linear function$

For (a)

Let y = 3^x

$y = e^{ln(3^x)} \\ \\y = e^{xln3} \\ \\ \frac{dy}{dx} = ln(3)e^{xln3} \\ \\\frac{dy}{dx} = ln(3)e^{ln(3^x)} \\ \\\frac{dy}{dx} = ln(3)3^x$

darlking · May 17, 2013

Thanks

Differentiation of LOG FUNCTIONS (1 Viewer)

darlking

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HeroicPandas

Heroic!

darlking

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HeroicPandas

Heroic!

darlking

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