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Need some help with my decision (2 Viewers)

RealiseNothing

what is that?It is Cowpea
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In chemistry, its significant figures, so u look at the question and the data given, and pick out the data that U HAVE USED (in this case the 5 grams of magnesium), how many significant figures is 5? Its 1 sig fig, so ur answer should be in 1 sig fig

so n = 0 (1sf) lol

this is a bad question i shouldve done 5.0001 grams

HOWEVER, say u did a question and u used 2 values from the information given: say 0.1001grams and 0.2grams, ur final answer will be in 1 sig fig as it is the lowest
n = 0 is not 1 sig fig though.
 

jnney

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You don't need to do general maths. Don't do it if you know you're not going to perform well in the subject.

:)
 

jaycoo

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You don't need to do general maths. Don't do it if you know you're not going to perform well in the subject.

:)
Wait wait what do you mean I don't need it? I'm good at maths. Lets just say the teacher supervises the class rather than actually "teaching" stuff.
 

ResourcesHSC

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I'd say as long as your comfortable with the chemistry calculations.
 

Menomaths

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Just a quick question... What are moles?
Amount of any substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as there are atoms in 12 grams of pure carbon-12
Dat state of confusion
 

jaycoo

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Amount of any substance that contains as many elementary entities (e.g., atoms, molecules, ions, electrons) as there are atoms in 12 grams of pure carbon-12
Dat state of confusion
I thought they were those spots on your skin that had hairs growing out of them HAHAHAHAHAHAHAHAHAAHAHAHAH no. ok. so every element has a mole/s
 

Menomaths

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I thought they were those spots on your skin that had hairs growing out of them HAHAHAHAHAHAHAHAHAAHAHAHAH no. ok. so every element has a mole/s
Your year 10 don't worry, if I tell you you might drop Chemistry
 

Menomaths

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A mole is the quantity of anything that has the same number of particles found in 12.000 grams of carbon-12. That number of particles is Avogadro's Number, which is roughly 6.02x10^23. A mole of carbon atoms is 6.02x1023 carbon atoms.
 

jaycoo50

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Example: Calculate the number of moles of 5 grams of magnesium (use the periodic table)
so, you would use, n= n/Mm,

find the Molar mass of magnesium from the periodic table, that should be easy. N = 5/Molar mass of magesium, I know it could get hard becasue you have'nt learnt all that yet, so relax "jaycoo" you still have about two years, while its good to learn ahead.
 

jaycoo50

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If I do maths would it help me? Do I really need maths? Either way I'm still keeping it. Just wondering though.
yes. do maths 2u atleast if you want to do, chemistry, maths 2u and ext 1 will help you to perfrom the calculations and understand the concepts in chemistry.

I am plainging to do maths ext 1 and 2 in year 12, my brother scored 99.95 this year at james ruse. He said if you do maths ext 1 and maths 2u at school, then chemistry becomes much easy, and doing maths ext 1 and 2 in year 12, chemistry will be much easily and you can also get a band 6.

I am planning to do maths ext 1 and maths 2u in year 11.
 
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jaycoo

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yes. do maths 2u atleast if you want to do, chemistry, maths 2u and ext 1 will help you to perfrom the calculations and understand the concepts in chemistry.

I am plainging to do maths ext 1 and 2 in year 12, my brother scored 99.95 this year at james ruse. He said if you do maths ext 1 and maths 2u at school, then chemistry becomes much easy, and doing maths ext 1 and 2 in year 12, chemistry will be much easily and you can also get a band 6.

I am planning to do maths ext 1 and maths 2u in year 11.
Thanks for the advice but that would be too much for me. This year I'm the top 5.2 maths class. I was recommended general maths.

Who are you? I see we have the same name.
 

jaycoo

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A mole is the quantity of anything that has the same number of particles found in 12.000 grams of carbon-12. That number of particles is Avogadro's Number, which is roughly 6.02x10^23. A mole of carbon atoms is 6.02x1023 carbon atoms.
Ill keep that in mind so it's familiar with me. Thanks :)
 

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