Section I - Multiple Choice (1 Viewer)

[Rafy]

Share your multiple choice responses here

 

[nippin]

Badcadaccb

 

[Ichan7]

lol

 

[shamunk1]

Bcbabdccbb

 

[RafH]

badabdacbc

guessed 7 and 10

 

[RealiseNothing]

b
a
d
a
b
d
c
c
b

forgot to answer 10 lols

 

[bunnypacman]

b
a
a (i had no idea)
b (got through half my working out and ran outta time so had to guess)
b
d
c
c
c (another guess)
? (cant remember what i put for 10 cause it was a guess :/ )

 

[panda15]

badabdccba

Completely guessed 10.

 

[drunkenmonkee37]

b
a
d
a
b
d
c
c
a
b(no idea)

 

[Siddy123]

i guessed d for 10
what was the answer to that revs per minute q?

 

[Locus]

i guess d for q10 as well - looked like a nice number

 

[BlugyBlug]

1b 2a 3d 4a 5b 6(?) 7c 8c 9b 10d (guess)

Forgot what i put for 6, pretty sure it's D though but i just did it now.

revs per minute = 100pi
v=rw
r=5, (period = 2pi/w) period was given so w =20pi

First time I've seen a pure circular motion q in a HSC paper lols.

 

[pHyRe]

D was defs wrong for q 10 i reckon, i saw it and realised it was 2^12, or 4GB = 4096 MB so it was there to trick us im pretty sure. I think i guessed C.... whatevs. fuck that

 

[hyphea]

D was defs wrong for q 10 i reckon, i saw it and realised it was 2^12, or 4GB = 4096 MB so it was there to trick us im pretty sure. I think i guessed C.... whatevs. fuck that

yep same here

 

[Trebla]

I think the answer to Q10 is (C).

 

[study1234]

Can someone please explain Question 10?

 

[psychotropic]

the answer to 10 is b

 

[Trebla]

First consider the unrestricted case. We have six people going into four rooms and each person has four choices which gives 4⁶.

Now subtract the cases where the restriction of 4 people per room is broken.

Case 1 - We have 5 people + 1 person. If we fix 5 people to be in the first room, the 1 person can go into the three other rooms. Similarly, if we fix the 5 people across the other rooms etc leading to 4x3 possibilities. However there are six possible people who can be that 1 person so there are 6x4x3 possibilities altogether.

Case 2 - We have 6 people and there are four possibile rooms they can be in.

Altogether we get 4⁶ - 6x4x3 - 4 = 4020

 

[psychotropic]

First consider the unrestricted case. We have six people going into four rooms and each person has four choices which gives 4⁶.

Now subtract the cases where the restriction of 4 people per room is broken.

Case 1 - We have 5 people + 1 person. If we fix 5 people to be in the first room, the 1 person can go into the three other rooms. Similarly, if we fix the 5 people across the other rooms etc leading to 4x3 possibilities.

Case 2 - We have 6 people and there are four possibile rooms they can be in.

Altogether we get 4⁶ - 4x3 - 4 = 4080

Case I is incorrect as you have to consider which person is excluded. this means that you have to multiple case 1 by 6, yielding 4020

 

[Trebla]

Case I is incorrect as you have to consider which person is excluded. this means that you have to multiple case 1 by 6, yielding 4020

Ah overlooked that. Corrected.