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complex no. (1 Viewer)

iEatOysters

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Do you have the answer? I think I got it... But I think it's wrong.
 

wagig

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My answer's root 2 haha, let me know if it's right and i'll show how i got it
 
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rumbleroar

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^ Yea pretty much
I think you can also use isosceles triangles?
 

wagig

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I did it a weird way i'm pretty sure,
I used vectors, cos rule () and algebra manipulation
 

braintic

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There is something wrong with this question.

Let z1=1, z2=1, z3=-1.
These satisfy the first requirement that they all have unit modulus.

So it satisfies the second requirement.


Now let z1=1, z2=i, z3=i.
Again the two requirements are met (you can check), but this time the answer is sqrt 2.

In fact I made a Geogebra construction, and you can get an infinite number of answers.

I think the question might be correct if you had asked for the MAXIMUM value of
 
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cineti970128

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What is the method of solving this?
Draw a circle with three point A, B, C representing z1, z2, z3.
By inspecting the formula, angle at A is 90. Hence using the semi circle angle property, BC must be a diameter through the origin.
Since z1 can b anywhere, so by inspecting the modulus |z1+z3| formed by adding z1 and z3 , hence > 0 and <2. I don't know how others got root 2.
 

Triage

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There is something wrong with this question.

Let z1=1, z2=1, z3=-1.
These satisfy the first requirement that they all have unit modulus.

So it satisfies the second requirement.


Now let z1=1, z2=i, z3=i.
Again the two requirements are met (you can check), but this time the answer is sqrt 2.

In fact I made a Geogebra construction, and you can get an infinite number of answers.

I think the question might be correct if you had asked for the MAXIMUM value of
|z1 - z2| doesn't equal |z1|-|z2|. I don't think something is wrong with the question.
 

braintic

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|z1-z2|^2 = |1-1|^2

I think that is a nonsense regardless
Not sure what it is you don't get, but all I've done is replace z1 by 1 and z2 by 1. Simple substitution. If you think year 7 substitution is nonsense, well ... what can I say.

Perhaps you could show me where I said that |z1 - z2| equals |z1|-|z2| .

And 'nonsense' is a non-countable noun, so it can't be preceded by 'a' unless you want to use it as an adjective for a countable noun.
 
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Triage

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Not sure what it is you don't get, but all I've done is replace z1 by 1 and z2 by 1. Simple substitution. If you think year 7 substitution is nonsense, well ... what can I say.

Perhaps you could show me where I said that |z1 - z2| equals |z1|-|z2| .

And 'nonsense' is a non-countable noun, so it can't be preceded by 'a' unless you want to use it as an adjective for a countable noun.
Sorry, my bad, I overlooked the substitution and thought you were just substituting in the modulus of z1 and z2. Seriously honest mistake of mine, nt trying to attack you in any way.
 

alficio

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Draw a circle with three point A, B, C representing z1, z2, z3.
By inspecting the formula, angle at A is 90. Hence using the semi circle angle property, BC must be a diameter through the origin.
Since z1 can b anywhere, so by inspecting the modulus |z1+z3| formed by adding z1 and z3 , hence > 0 and <2. I don't know how others got root 2.
Just wondering isn't it possible that A isn't 90 degrees?
 

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