K kasser New Member Joined Jun 7, 2014 Messages 18 Gender Undisclosed HSC N/A Jun 7, 2014 #1 How to solve AB is a diameter and AC is a tangent. Prove that c) AB^2 + AC^2 = BC^2 I also proved before that AB^2 = BC.BD and AC^2 = BC.DC? Thanks
How to solve AB is a diameter and AC is a tangent. Prove that c) AB^2 + AC^2 = BC^2 I also proved before that AB^2 = BC.BD and AC^2 = BC.DC? Thanks
Shadowdude Cult of Personality Joined Sep 19, 2009 Messages 12,145 Gender Male HSC 2010 Jun 7, 2014 #2 kasser said: How to solve AB is a diameter and AC is a tangent. Prove that c) AB^2 + AC^2 = BC^2 I also proved before that AB^2 = BC.BD and AC^2 = BC.DC? Thanks Click to expand... well...
kasser said: How to solve AB is a diameter and AC is a tangent. Prove that c) AB^2 + AC^2 = BC^2 I also proved before that AB^2 = BC.BD and AC^2 = BC.DC? Thanks Click to expand... well...
T TL1998 Member Joined Apr 19, 2014 Messages 39 Gender Male HSC 2016 Jun 11, 2014 #3 Shadowdude said: well... Click to expand... A simpler method is by oserving that triangle CAB is right angled at A (since the tangent to a radius is perpendicular). Then by pytahogras' theorem, AB^2 + AC^2 = BC^2
Shadowdude said: well... Click to expand... A simpler method is by oserving that triangle CAB is right angled at A (since the tangent to a radius is perpendicular). Then by pytahogras' theorem, AB^2 + AC^2 = BC^2