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How to solve? (1 Viewer)

Thread starter kasser
Start date Jun 19, 2014

K

kasser

New Member

#1

AB is a diameter of a circle and CD is a chord drawn perpendicular to A cutting it at X. Prove that CX ^2 = AX.XB

B

braintic

Well-Known Member

#2

This is straight Intersecting Chords Theorem, where CX=DX because a radius perpendicular to a chord bisects the chord.

F

Fiction

Active Member

#3

Isn't this property 16...?

B

braintic

Well-Known Member

#4

Fiction said:
Isn't this property 16...?

How is anyone meant to know what you mean by property 16?
Where do you get that number from?

seanieg89

Well-Known Member

#5

If you want to prove this property, it comes out quickly from considering similar triangles.

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