HSC 2014 Maths Marathon (archive) (2 Viewers)

[dunjaaa]

Re: HSC 2014 2U Marathon

Yes, that's correct

 

[photastic]

Re: HSC 2014 2U Marathon

No, i was referring to the integration of 1/xlnx because the person who attempted it used u-sub which is 3u

 

[hi im trash]

Re: HSC 2014 2U Marathon

How would you the first one using 2u method only?

i think its just a 1 mark question, because 1/(xlnx) can be seen as (1/x)/(lnx), hence, ln(lnx)+c.

Also the answer to this question http://postimg.org/image/id86iq0qb/ = ((pi^pi)-1)/ln(pi). (working, you just move the lnpi from the rhs to lhs and bingo)

also guys... how do you guys find these questions?! :OOO

 

[Sy123]

Re: HSC 2014 2U Marathon

 

[Thank_You]

Re: HSC 2014 2U Marathon

How would you the first one using 2u method only?

Are you talking about f 1/xlnx ? If so, then I actually wouldn't have a clue if you could differentiate via 2u :/

 

[photastic]

Re: HSC 2014 2U Marathon

Are you talking about f 1/xlnx ? If so, then I actually wouldn't have a clue if you could differentiate via 2u :/

Dw. Hi im trash solved it

Can you integrate two dx's in 2u?

 

[hi im trash]

Re: HSC 2014 2U Marathon

Assuming it's 1 dx instead of two, it would eventually turn out like 1/x/lnx/ln (lnx) which integrated would be ln (ln (lnx))) + C. If it's two 2dx I'd have no clue

 

[dunjaaa]

Re: HSC 2014 2U Marathon

yeah basically the same idea, [1/xln(x)]/[ln(ln(x))] and integrate

 

[dunjaaa]

Re: HSC 2014 2U Marathon

Question:

 

[integral95]

Re: HSC 2014 2U Marathon

Question: View attachment 30783

Lol i remember seeing that question in the Kings 4U paper, funny how it could actually be done with 2U technique.

 

[Sy123]

Re: HSC 2014 2U Marathon

Question: View attachment 30783

I know this is possible with 2U knowledge, but I think these sort of questions are best left to the higher marathons, most students doing 2U anyway don't really want questions of that difficulty

 

[dunjaaa]

Re: HSC 2014 2U Marathon

Sorry. A better question: Find the volume of the solid of rotation when the region bounded by the curve y=(x-4)(8-x) and the lines x=4, x=8 and y=10 is rotated about the x-axis.

 

[hi im trash]

Re: HSC 2014 2U Marathon

Question: View attachment 30783

I) it's a gp with r = -x
ii) integrate x^2n+1/1+x = 1-1/2+1/3-1/4.....+1/2n+1 - ln2
iii) since n approaches infinity, 1 /2(n+1) approaches 0. And since I is less than 1/2(n+1), hence I < or equal to 0
Iv) I don't really know how to do this one, but I feel like it's fishy cause I don't think k can = 0

 

[dunjaaa]

Re: HSC 2014 2U Marathon

Yeah, was a typo. It was meant to be k=1. Hint for (iv), use part (ii) and (iii).

 

[hi im trash]

Re: HSC 2014 2U Marathon

Yeah, was a typo. It was meant to be k=1. Hint for (iv), use part (ii) and (iii).

have already tried assuming k=1, ended up getting a result that was opposite in sign compared to II so ))))): sadday

 

[dunjaaa]

Re: HSC 2014 2U Marathon

Sorry another typo . It's meant to be (-1)^(k+1)

 

[dunjaaa]

Re: HSC 2014 2U Marathon

.

 

[dunjaaa]

Re: HSC 2014 2U Marathon

bump

 

[hi im trash]

Re: HSC 2014 2U Marathon

Sorry another typo . It's meant to be (-1)^(k+1)

Ah that explains everything then

Sorry. A better question: Find the volume of the solid of rotation when the region bounded by the curve y=(x-4)(8-x) and the lines x=4, x=8 and y=10 is rotated about the x-axis.

also do you mean y=-10?

 

[dunjaaa]

Re: HSC 2014 2U Marathon

Nothing is wrong with the question, I promise haha