General Thoughts: Mathematics (1 Viewer)

[WileyWanimal]

Is someone going to upload some solutions??

 

[yma]

I got a concave down parabola with TP at 1 and roots at -2 and 3.
Don't know if that's right though. :s

You're probably right.. I got 2 upward concave in my graph.. my graph looks very weird


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[WileyWanimal]

minimum s.p. at (-2,0) , max at (1, ...) and cuts x-axis at x = 3

well you have SPs where f'(x)=0, so surely the derivitive graph=0 where there were SPs on the original graph... Doesn't it?

idk, now I'm doubting myself.

 

[zeroni]

any estimates for band 5? lel

 

[enigma_1]

any estimates for band 5? lel

~65 cut off maybe

 

[zeroni]

ah okay, cheers. Hopefully I'm not *too* fucked

 

[Chocolatebubble]

~65 cut off maybe

I think the exam was a little easier (compared to 2013), wouldn't it be higher?

 

[enigma_1]

I think the exam was a little easier (compared to 2013), wouldn't it be higher?

The maybe high 60s, definitely not in the 70s for the cut off though

 

[orcevalm]

can anyone (if bothered) post the answers up for the MC ? i hope i got them right :/

 

[chrisdelinet]

well you have SPs where f'(x)=0, so surely the derivitive graph=0 where there were SPs on the original graph... Doesn't it?

idk, now I'm doubting myself.

A is horizontal pt of inflexion, therefore at A, y' = 0 (reason why it touches x-axis) but values to the left and right of A will not change the sign of y' (we can see that y' > 0 for A < x and x> A). therefore the reason for a minimum at A

B is a pt of inflexion, meaning that y'' = 0 which means a maximum above the x - axis as y' > 0 for B < x and x > B.

lastly because there is a maximum at C, i'll cut the x-axis from above as y' > 0 for C < x and y' < 0 for x > C

therefore shape of derivative graph is \/\

 

[hi im trash]

can anyone (if bothered) post the answers up for the MC ? i hope i got them right :/

i think theres a thread about MCQs already, could try looking there

what was the band 6 cut off for last year and the year before that? :S

 

[Technoash]

can anyone (if bothered) post the answers up for the MC ? i hope i got them right :/

These are all from memory. Im not working any out again lol

1. A
2. B
3. D
4. C
5. B (i think)
6. D
7. B
8. A or D (the answer is B or C lol i fkd up)
9. A
10. A

Did I mess up anywhere?

 

[chrisdelinet]

These are all from memory. Im not working any out again lol

1. A
2. B
3. D
4. C
5. B (i think)
6. D
7. B
8. A or D (the answer is B or C lol i fkd up)
9. A
10. A

Did I mess up anywhere?

i believe 8 is supposed to be C and 10 is D

 

[nexusbrah]

These are all from memory. Im not working any out again lol

1. A
2. B
3. D
4. C
5. B (i think)
6. D
7. B
8. A or D (the answer is B or C lol i fkd up)
9. A
10. A

Did I mess up anywhere?

First one is B. 99% sure

 

[trungduong12]

First one is B. 99% sure

Isnt it 5 is D?


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[WileyWanimal]

A is horizontal pt of inflexion, therefore at A, y' = 0 (reason why it touches x-axis) but values to the left and right of A will not change the sign of y' (we can see that y' > 0 for A < x and x> A). therefore the reason for a minimum at A

B is a pt of inflexion, meaning that y'' = 0 which means a maximum above the x - axis as y' > 0 for B < x and x > B.

lastly because there is a maximum at C, i'll cut the x-axis from above as y' > 0 for C < x and y' < 0 for x > C

therefore shape of derivative graph is \/\

;( Yes, you're right...
Would I get 2/3 because I had it right at B and C, and I at least knew it touched the axis at A?

 

[chrisdelinet]

Isnt it 5 is D?


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no mate, that'll give both equations positive gradients therefore can't be perpendicular to each other

 

[phcan]

Omg same here i think i left like 20 marks worth of questions fml

 

[trungduong12]

no mate, that'll give both equations positive gradients therefore can't be perpendicular to each other

I wanna cry T_T
Forgot it says perpendicular

!!!!


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[WileyWanimal]

i believe 8 is supposed to be C and 10 is D

I agree.