Would someone please explain molar heat of combustion? (I'm so confused about it I'm not even sure if it's called that!)
Some worked examples would be great as well.
Molar heat of combustion:
Heat of combustion simply means the amount of heat released when burning something. When we burn 1 mole of that something we call the heat released molar heat of combustion.
So how do we calculate it?
Well, we burn a certain amount (say 5 grams) of something and see how much heat it releases.
Let us say for the sake of example it gave us 500j. We then say if 5 grams gives us 500j, how much would 1gram give us? (Simple maths) 1g gives us 100j.
Then we say how much does 1 mole of this substance weight (again simple maths, mass=number of moles X molar mass). We find for example 1 mole weighs 3grams.
Then we say if 1 gram gives us 100j then how much would 3 grams give us? The answer would be 300j.
So now we found what the molar heat of combustion is (heat released per mole).
In the ethanol experiment, we use the (delta) H = mC(delta) T.
m is the amount of water we used (weight in grams) and delta T is the change in temperature, and C is the constant 4.18.
Check out this example as well:
Question: In an experiment, 1.4g of butanol was burnt and the heat collected by a metal can containing
200g of water. The water temperature rose by 23oC.
Heat absorbed by water in the calorimeter:
ΔH = -mCΔT
= - 200 x 4.18 x 23
= - 19,228 J
≅19 kJ of heat released.
This is the heat released for 1.4g of butanol burnt.
∴ Heat of Combustion per gram = 19/1.4 = 13.57 kJ/g
≅14 kJ/g
Molar Mass (butanol) = 74.1g
∴ Molar Heat of Combustion = 13.57 x 74.1
≅ 1000 kJmol-1.
Hope that answers your question you can go to:
https://www.uhsinternational.com/hsc-chemistry-tutors.html and download the sample resource it has got more explanation about molar heat of combustion
and share the link ;-)