That's easy, does the HSC even ask those questions?Next question:
Distinguish between the end point and the equivalence point in an acid-base titration.
Yeah sometimes in multiple choice for sympathy marksThat's easy, does the HSC even ask those questions?
Endpoint: The point at which the indicator in the solution changes colour
Equivalence point: The point at which the reaction is complete
1. At the beginning the hydrogen ion concentration is greater than at the end as there is less H2CO3 in solutionIndependent Trial Paper 2011
A student measures the pH of a can of soft drink, immediately after it is opened, then at 15 minute intervals as shown in the table.
Time 0 , 15 , 30 , 45 , 60 , 75 , 90 , 105 , 120
pH 4.5 , 5.9 , 6.5 , 6.7 , 7.1 , 7.3 , 7.4 , 7.4 , 7.5
Compare the initial hydrogen ion concentration with that after 2 hours (2 MARKS)
Explain the changing pH of the soft drink in terms of Le Chatelier’s principle, and the properties of carbon dioxide. (3 MARKS)
Which is what i wrote... 10^(-4.5)/10^(-7.5) =1000 ...Actually...i found the answer to part 1 only.
IT says, the difference in pH from start to end is 3. Hence, the initial hydrogen ion concentration is 1000 times more than that after 2 hours.
This is soo dead
Don't worry after trials we'll all be posting questions because that's when we have time to do any subject we wish to work onIts holidays, nothing new >.>
I need inspiration to do English and ChemistryDon't worry after trials we'll all be posting questions because that's when we have time to do any subject we wish to work on
Disturbed. Le Chatelier's principle states the equilibrium will shift to the left, due to an increase in pressure. The equilibrium attempts to 'balance' itself by becoming equimolar hence shifts left.It's been a while...
Suppose that you have a closed system that is under equilibrium (all gases) and the equation is: X(g) + 4Y(g) <-> 8Z(g). If I pump in Argon gas at constant pressure, what does it do to the system? Is equilibrium disturbed or undisturbed? Justify your answer
undisturbed. Argon gas is an inert gas therefore will not affect the equilibrium as it doesn't affect partial pressure. No changes will happen to the system.It's been a while...
Suppose that you have a closed system that is under equilibrium (all gases) and the equation is: X(g) + 4Y(g) <-> 8Z(g). If I pump in Argon gas at constant pressure, what does it do to the system? Is equilibrium disturbed or undisturbed? Justify your answer
but doesnt it still increase the pressure?undisturbed. Argon gas is an inert gas therefore will not affect the equilibrium as it doesn't affect partial pressure. No changes will happen to the system.
.Suppose that you have a closed system that is under equilibrium (all gases) and the equation is: X(g) + 4Y(g) <-> 8Z(g). If I pump in Argon gas at constant pressure, what does it do to the system? Is equilibrium disturbed or undisturbed? Justify your answer
If the pressure remains the same, the volume needs to increase if your adding another gas, so the equilibrium will actually shift to compensate for the increase in volume.no, because the initial premise of it was that neither pressure increased or decreased. so therefore, because it's at constant pressure, there was no imposed change and hence the equilibrium remains the same
thus, it has to be undisturbed like fiction said before
oh, does it?If the pressure remains the same, the volume needs to increase if your adding another gas, so the equilibrium will actually shift to compensate for the increase in volume.
Relate volume/pressure for ideal gases.oh, does it?
so it comes back to the inverse relationship of volume and pressure yes?
but is thunderstorm's answer correct?
adfalsdjfkIf the pressure remains the same, the volume needs to increase if your adding another gas, so the equilibrium will actually shift to compensate for the increase in volume.