Inverse trig problem (1 Viewer)

[Thylacine]

Find the volume of the solid formed if the curve y = sec^-1(x) is rotated about the x-axis from x = 0, 0.5, using the trapezoidal rule with 5 subintervals.
MIF challenge exercise 7 Q10 (a

Thanks for any help. I get a different answer to BOB.

 

[leehuan]

Not too sure how you got an answer for this question. This question gave the MX1 students of my cohort this year a ton of grief, until my fellow X2 students and I stated that y=sec^-1(x) doesn't even have a GRAPH between x=-1 and x=1. If you got no graph, what can you rotate?

I have no idea what Grove was trying to say in making that question. It's faulty.

 

[Squar3root]

inb4enigma

 

[enigma_1]

y u no use cambridge

 

[photastic]

Find the volume of the solid formed if the curve y = sec^-1(x) is rotated about the x-axis from x = 0, 0.5, using the trapezoidal rule with 5 subintervals.
MIF challenge exercise 7 Q10 (a

Thanks for any help. I get a different answer to BOB.

Assume this is a table:
x 0 0.1 0.2 0.3 0.4 0.5
y^2 (Values when you Sub the x into y squared)

V = πh/2(1st + last + 2(middle))
V = 0.05π(arcsec^2(0)+arcsec^2(0.5)+2(arcsec^2(0.1)+arcsec^2(0.2)+arcsec^2(0.3)+arcsec^2(0.4))

This question is broken, which is why it is challenging.

 

[Thylacine]

Not too sure how you got an answer for this question.

I can see how I got an answer by using the wrong method (1/cos(x))^2 .

Thanks for the help. I should have looked at a graph of the curve before I started.
MIF has wasted so much of my time with wrong answers.

 

[enigma_1]

I can see how I got an answer by using the wrong method (1/cos(x))^2 .

Thanks for the help. I should have looked at a graph of the curve before I started.
MIF has wasted so much of my time with wrong answers.

Why do you use mif