Polynomials (1 Viewer)

[Speed6]

This is a polynomial question from a past paper, is there a non-calculus based approach for this particular question?

Ty

 

[AztecWarrior]

factor theorem, long division

 

[Speed6]

factor theorem, long division

So I should just keep trying the factor theorem until I can get 0? Might as well as as keep trying to find that number.

 

[Drsoccerball]

This is a polynomial question from a past paper, is there a non-calculus based approach for this particular question?

Ty

Yes the first question definitely requires calculus to find m and n since no other roots are given. However for part (ii) instead of doing long division a simple factorisation would do the job.
since now you know all the coefficients of tje polynomial (from i) compare coefficients and factorise.

 

[InteGrand]

I think he was asking if there is a non-calculus approach for part (i), since it's obvious you don't need it for part (ii).

 

[Speed6]

Hold on, is the factor theorem the same as the remainder theorem or no?

 

[Speed6]

I think he was asking if there is a non-calculus approach for part (i), since it's obvious you don't need it for part (ii).

Yeah, I can't use calculus for the first part.

 

[Drsoccerball]

I think he was asking if there is a non-calculus approach for part (i), since it's obvious you don't need it for part (ii).

Well he could do the unintelligent thing and find the rest of the roots by multiplaction of roots and multiplication by 3's but its much longer than differentiation

 

[Speed6]

It's a 2 mark qstn so I'm not going to sit there and use up all my time.

 

[Drsoccerball]

It's a 2 mark qstn so I'm not going to sit there and use up all my time.

Then just use calculus ahahah

 

[InteGrand]

Hold on, is the factor theorem the same as the remainder theorem or no?