-
Finished your HSC? Check out our University Discussion, Non-School forums or help out next year's HSC students! -
YOU can help the next generation of students in the community! Share your trial papers and notes on our Notes & Resources page
Physics Question - Motors and Generators Help (1 Viewer)
- Thread starter Khan.Paki
- Start date
Squar3root
realest nigga
a) right hand rule
b) use t = mgd
c) since there is no motion you can equate mgd = torque to solve for magnetic field strength
b) use t = mgd
c) since there is no motion you can equate mgd = torque to solve for magnetic field strength
Squar3root
realest nigga
nws 
Squar3root
realest nigga
left of the page cos magnetic field goes from North -> South
but why is the south end to the left? How do you know?
Squar3root
realest nigga
idk cos there is nothing on the right of the magnet I guess?
The fact that there is no south pole in the diagram makes no difference -> whenever you have a single pole present in a diagram it should be automatically assumed that it's opposite pole exists somewhere (it's not possible to have a single pole exist by itself) - they just sometimes don't show it in a question, just accept it Re. how do you figure out direction of field, I understand the confusion because only a single pole is shown, but the wire on the far LHS is close enough for the field to be assumed to being perpendicular to the current. A lot of assumptions I know. But you get used to it with enough practice
Fizzy_Cyst
Well-Known Member
It actually does matter!The fact that there is no south pole in the diagram makes no difference -> whenever you have a single pole present in a diagram it should be automatically assumed that it's opposite pole exists somewhere (it's not possible to have a single pole exist by itself) - they just sometimes don't show it in a question, just accept it Re. how do you figure out direction of field, I understand the confusion because only a single pole is shown, but the wire on the far LHS is close enough for the field to be assumed to being perpendicular to the current. A lot of assumptions I know. But you get used to it with enough practice
This question wanted you to equate torque of ONE SIDE OF THE COIL ONLY!!
It wanted to assume that the magnetic field lines had spread out.
Notes from marking centre for that question
Weaker responses demonstrated some misunderstandings regarding torque and force. Common errors included incorrectly equating torque with force and assuming the magnetic field was constant in the equation τ = nBIAcosθ.
Last edited:
Fizzy_Cyst
Well-Known Member
Please see attached.
It is from 2009 HSC.
Note: they used nBil * d where d is distance from axle to coil in the field.
No guarantee success one will be right btw, lol.
Last edited:
"This question wanted you to equate torque of ONE SIDE OF THE COIL ONLY!!"
What does that mean? How do we know? How could the question be worded so that it wasn't only on one side.
"It wanted to assume that the magnetic field lines had spread out."
What does this mean?
" Common errors included assuming the magnetic field was constant in the equation τ = nBIAcosθ"
Isn't it? What does this mean?
And if current is moving anti-clockwise in the coil, and the magnetic field direction is left, why is the weight on side X. Shouldn;t it be on side Y?
Last edited:
PhysicsMaths
Active Member
- Joined
- Dec 9, 2014
- Messages
- 179
- Gender
- Male
- HSC
- 2015
The question says that the mass is placed on side X OR side Y, meaning that it wants you to calculate the torque created by that mass. If the same mass was placed on the other side of the coil, then the torques created by both of the masses would cancel out, and you would have no rotational moment (due to mass on side Y creating a clockwise torque, and a mass on side X would produce an anti-clockwise torque)
Regardless if there is a north or south pole located on the other side, what you have to assume that the magnetic field lines are spread out, and are moving out of the north pole magnet. This means that you can assume that the magnetic field lines are travelling to the right.
The magnetic field is not constant, because the magnetic field lines passing through side X will be greater than side Y. What you would have to use is T = fd, where f is the force created by the mass (mg), and d is the perpendicular distance from the pivot to the point of rotation.
The reason why its not on side Y is because the magnetic field lines passing through that side is almost negligible, so you assume its on side X