Maff Q (1 Viewer)

[axwe7]

Don't quite understand what to do here.

Cheers,
Axwe7.

 

[anomalousdecay]

part b

f(a) = 2a
f(b) = 2b
f(a) + f(b) = 2a + 2b
f(a+b) = 2 (a + b) = 2a + 2b

So, clearly for all a and b, f(a) + f(b) = f(a+b) = 2a + 2b

part c

f(a) = a + 1
f(b) = b + 1
f(a) + f(b) = a + b + 2
f(a+b) = (a + b) + 1 = a + b + 1

clearly, we can see that

for all a and b.

Try out the other exercises for yourself and see how you go.

 

[Green Yoda]

Basically just sub in a and b into x where necessary and see if f(a) + f(b) = f(a+b). E.g
Part a:
f(a)=a
f(b)=b
f(a)+f(b)= a+b
----------------------------
f(a+b) = a+b
----------------------------
∴ f(a)+f(b)=f(a+b)

 

[Green Yoda]

Btw is that cambridge 3u or year 10?

 

[axwe7]

Btw is that cambridge 3u or year 10?

Yo man, haven't been on much, sorry about that, but to answer your question, it is Cambridge 3U.