What soulPeople on the confessions thread talk about vehicles and use the term MX5...
That automagically registers in my head as Mathematics Extension V.
._.
save my soul pls
Haha
Jks
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What soulPeople on the confessions thread talk about vehicles and use the term MX5...
That automagically registers in my head as Mathematics Extension V.
._.
save my soul pls
MX∞People on the confessions thread talk about vehicles and use the term MX5...
That automagically registers in my head as Mathematics Extension V.
._.
save my soul pls
MXπ
um.
i do that in 2U lelI totally used pseudo-"inspection" to save time on 4U today.
It was one of those "Hence prove the the point T is T(..., ...)" which is done through simultaneous equations
I solved for y simultaneously, then just said "Substituting this back into the first equation gives x = [xcoord from question]" rather than actually dealing with the equation twice
usually I consider the quotient and product of the x y co-ordinates... That's most of the "hard" locus questions.I totally used pseudo-"inspection" to save time on 4U today.
It was one of those "Hence prove the the point T is T(..., ...)" which is done through simultaneous equations
I solved for y simultaneously, then just said "Substituting this back into the first equation gives x = [xcoord from question]" rather than actually dealing with the equation twice
Oh no it was heaps easy, it's was just to prove that the coordinates were something. I think it was T(2cpq/(p+q), 2c/(p+q)). It was the point of intersection of the tangents at two points on a rectangular hyperbola. In the next part pq was assumed to be some constant (C) and so the locus is y = x/Cusually I consider the quotient and product of the x y co-ordinates... That's most of the "hard" locus questions.
The rest are impossible to see (and hence require magic) and the remaining are usually so obvious that the question can be handwaved in one line.
that's so easy I laugh.Oh no it was heaps easy, it's was just to prove that the coordinates were something. I think it was T(2cpq/(p+q), 2c/(p+q)). It was the point of intersection of the tangents at two points on a rectangular hyperbola. In the next part pq was assumed to be some constant (C) and so the locus is y = x/C
LOLCurious: can I use matrices to solve simultaneous equations in my 2u exam? lel
Wow gees your simultaneous equations in 2U aren't even hard and you want matrices?!Curious: can I use matrices to solve simultaneous equations in my 2u exam? lel
Are you sure you're allowed to use matrices for the Conics section in HSC? Because that'll really trivialise some of the questions they ask.LOL
I know you can use Matrices to solve problems of the Conic sections in 4U (source: Olympiad tutor)
I'm not sure 2U affords students the same flexibility.
for the lolsWow gees your simultaneous equations in 2U aren't even hard and you want matrices?!
SCREAMSLOL
I know you can use Matrices to solve problems of the Conic sections in 4U (source: Olympiad tutor)
I'm not sure 2U affords students the same flexibility.
Only for the actual HSC. No idea what your school demands of you.SCREAMS
WHAT
That's so much easier I'm literally sobbing inside I wish I knew this eariler