Based on my hypothesis I need the one that weighs more to have a larger surface area to volume ratio.
I know larger cells have a smaller sa/vol ratio, and that small cells with large sa/vol ratios are more efficient (e.g. a small cup of coffee will cool quicker than a large cup of coffee)
The coke bottles appear to be the same size right, but one weighs more than the other.
Osmosis should occur quicker in the one with the largest sa/vol ratio. I'm just not sure if that can be the one that weighs more.
The person that was responsible for taking measurements was too slack to do so, so I'm left guessing.
ok so basically
then you have a problem lol
one will weigh more than the other based on either 1) one is more dense than the other or 2) one is has more volume than the other
or 3) both
basically what we know is that they are the same shape
so that means the surface area is dependent on the volume
if the reason for a weight difference is because of a difference in density only, that means both will have the same surface area to volume ratio
if the reason for a weight difference is because of a difference in volume only, that means they will have different surface area to volume ratios, and actually the one that weighs more will have a greater volume and so will have a lower surface to volume ratio lol
edit: considering that they are lollies i would assume volume would be same, and density would be the variation
so they should have same sa:v ratio
edit2: now that i think about it, if the shapes are the same then sa is directly proportional to v, and if v changes so does sa and so the ratio will be the same?