Gravitational potential energy (GPE) (1 Viewer)

[eyeseeyou]

Is my answer right?

idk

 

[eyeseeyou]

How do I calculate the period

Also does Period represent gravitational constant in the orbital velocity formula?

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[pikachu975]

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lol waste of time doing it when there's no solutions....

 

[Green Yoda]

lol waste of time doing it when there's no solutions....

I did a similar question today but a bit harder in its wording..I applied the same technique..so I think it is correct.

 

[eyeseeyou]

lol waste of time doing it when there's no solutions....

How's it a waste of time?

 

[pikachu975]

How's it a waste of time?

Because we could've done it completely wrong and not know lol

 

[trecex1]

How's it a waste of time?

Why don't you just think about the questions before posting? You look at what you have and what you want and see which equation(s) to use. There's a reason why people who don't do maths/general can still do HSC physics - there are no tricks involved in calculations. Maybe self learning isn't working out so well?

 

[eyeseeyou]

r=2.5x10^6m + the altitude given

If we rearrange the ΔGPE formula we get E(p)=Gm1m2(1/r(i) - 1/r(f))
∴1x10^7=Gm1m2(1/(2.6x10^6) - 1/(2.7x10^6))
∴Gm1m2=7.02x10^14
Now we calculate the ΔGPE for the fall by subbing in Gm1m2 as 7.02x10^14
∴ΔGPE=7.02x10^14(1/(2.7x10^6) - 1/(2.66x10^6))
∴ΔGPE=-4.9x10^6 J

What?

 

[pikachu975]

What?

10 MJ = 10 x 10^6 Joules
= 1 x 10^7 Joules

 

[eyeseeyou]

10 MJ = 10 x 10^6 Joules
= 1 x 10^7 Joules

Thanks

 

[eyeseeyou]

r=2.5x10^6m + the altitude given

If we rearrange the ΔGPE formula we get E(p)=Gm1m2(1/r(i) - 1/r(f))
∴1x10^7=Gm1m2(1/(2.6x10^6) - 1/(2.7x10^6))
∴Gm1m2=7.02x10^14
Now we calculate the ΔGPE for the fall by subbing in Gm1m2 as 7.02x10^14
∴ΔGPE=7.02x10^14(1/(2.7x10^6) - 1/(2.66x10^6))
∴ΔGPE=-4.9x10^6 J

Why'd u switch the numbers around?

 

[Green Yoda]

Why'd u switch the numbers around?

To account for the negative in -(Gm1m2) so to make it positive we do r(i)-r(f) instead of r(f)-r(i)

 

[eyeseeyou]

To account for the negative -(Gm1m2) so to make it positive we do r(i)-r(f) instead of r(f)-r(i)

Oh right right