Easiest Paper Ever (2 Viewers)

[whatarethoose]

30c u had to use the cosine

 

[Bliske]

correct the SILVER coins were 185. You had to add the 20 gold with 185 to get 205 (total coins

But, if their was 185 silver coins and 20 gold coins that would mean that their was a 20/205 chance of selecting the gold coin which makes the probability of selecting a gold coin 4/41, where the probability of selecting a gold from the previous answer was 4/37. So, their must have been 185 coins in total because 20/185 = 4/37.

 

[BigBusty]

Can someone clarify the energy question. Was it 505 x 5 x 0.35 + 990?

 

[Bliske]

I cant recall the equations but I did substitute the values back into the equation and got s = 10 x = 64.

 

[BigBusty]

yep pretty sure that was right for the last question

 

[BLIT2014]

I cant recall the equations but I did substitute the values back into the equation and got s = 10 x = 64.

That is correct.

 

[Bliske]

Anyone hoping for a state ranking ?

Fingers crossed. Although, their was one question involving future value that I am not completely sure I put the right values in.

 

[BLIT2014]

i got s = 10 x = 64

Good work

 

[BLIT2014]

Can someone clarify the energy question. Was it 505 x 5 x 0.35 + 990?

Yes that is what I get.


Cost function:

Y=mx+b
= 0.35*$500*5+ $990
=$1873.75

 

[BLIT2014]

But, if their was 185 silver coins and 20 gold coins that would mean that their was a 20/205 chance of selecting the gold coin which makes the probability of selecting a gold coin 4/41, where the probability of selecting a gold from the previous answer was 4/37. So, their must have been 185 coins in total because 20/185 = 4/37.

Good explanation. If people are curious there are 165 silver coins, and 20 gold coins most likely.

 

[Memphis Depay]

Yep you're right. That is correct

 

[Bliske]

Concerning the question where they asked you to verify that the correlation coefficient to three decimal places: was this in the parameters of the syllabus? My teacher taught us that it wasn't in the scope of syllabus for us to work it out - they said that questions would always have to give you the correlation coefficient. Regardless, I learnt how to do it, and so I got the answer, but I'm wondering if this happened to anyone else?

 

[BLIT2014]

the marshmalow i got 190 something for the volume

and the coin one was 185 right?

The volume is 58.9 for the marshmallow one.

V=π*r^2*h
=π*2.5^2*3
=58.9cm^3

 

[BigBusty]

For M = A(1.1)^ , the growth rate is 10% right?

 

[BLIT2014]

Concerning the question where they asked you to verify that the correlation coefficient to three decimal places: was this in the parameters of the syllabus? My teacher taught us that it wasn't in the scope of syllabus for us to work it out - they said that questions would always have to give you the correlation coefficient. Regardless, I learnt how to do it, and so I got the answer, but I'm wondering if this happened to anyone else?

Asking to verify the calculation sounds well within the scope of the syllabus. I'm pretty sure I got taught how to do verify it too.

 

[Bliske]

For M = A(1.1)^ , the growth rate is 10% right?

Yes. Because the equation is M = A(1.1)^x, which is just this M = A(1+10%)^x. So, the growth rate is 10%.

 

[Bliske]

What question number was this?

29) D)i

 

[Bliske]

The volume is 58.9 for the marshmallow one.

V=π*r^2*h
=π*2.5^2*3
=58.9cm^3

This is the answer for part I. From memory the answer from part II was around 190, I think that is what they are referring to.

 

[BLIT2014]

This is the answer for part I. From memory the answer from part II was around 190, I think that is what they are referring to.

Oh right I couldn't be bothered to solve the second part, 190cm^3 sounded a tad large to me when I looked at part 1!

 

[BLIT2014]

29) D)i

I think your teacher advised you guys poorly unfortunately although it does sound like something a lot of teachers wouldn't have taught their students.