ok how does that equation even work....
HSC Extension 1 Mathematics Predictions / Thoughts (1 Viewer)
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These are just based on a set cutoff guess though, but I think the uncertainty zone takes care of that.
Aligning is pretty much a linear process
probably 2/3 like most people lol im fairly sure most the state lost a mark on that
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If rigour is not important for the HSC markers then it would probably be sufficient to simply test one point to find c (i.e. most people would get full marks). However, the whole idea of testing for the different domains was for the sake of rigour (i.e. just in case there is some weird piecemeal function where each piece differs by a constant). If the HSC markers expect that additional level of rigour then it would make sense for them to also expect due considerations of where the derivative is undefined but the function is defined.
I cannot say for sure how rigorously the HSC markers will scrutinise it, but I suspect the intended solution they had in mind was what I had in my earlier post (the arguments of common points at the edges of the domain). Otherwise, I think the question is extremely generous to be worth 3 marks.
Yes, but substituting once is a problematic in the sense that there exists functions that do differ by a constant e.g arctanx + arctan*(1/x) between continuous portions.
However, I think(?) that there exists no functions that upon substituting the endpoint of each continuous portion of the domain, if the derivative is only undefined at such endpoints, that the functions are not equal. So in some sense, by only substituting one point, there is potential to form incorrect equalities, but not by failing consider the derivative domain and endpoints.
Therefore, wouldn't failing to substitute two points appear to be a rather more serious error in terms of the rigour?
Another way to put it is to conclude whether it is reasonable to make the deduction that endpoint equality at discontinuity + equal integral implies equal function as you do in your main solution. If it is, I don't see a reason why marks should be deducted for immediately jumping to the conclusion they are equal after substituting two endpoints.
If it is not acceptable, the only solutions that should be accepted are the double triangle, and endpoint equality check + double substitution in the continuous branches outside of the endpoints.
If it is not acceptable, the only solutions that should be accepted are the double triangle, and endpoint equality check + double substitution in the continuous branches outside of the endpoints.
Well my equation puts you at a 98, which I think is about right
how about a 68/70? Does that convert to a 98 as well?
That just makes it to 99!
DOes that mean that 69 and 70 will be 100? If so does that mean the 1 mark difference between 69 and 70 does not matter? Also when they give you your final mark, is it out of 50 or 100? Thanks in advance mate!
69 is probably is still 99 and 70 will obviously be 100. Not sure about the final mark tbh. But it definitely does matter, raw marks are used by uac for scaling. State ranks are also held to two decimal places as well.
tokyocalling
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im not positive about this but i think you get your mark out of 100 if you take 4 units of math but 50 if you only take 3 units. The mark difference between 69 and 70 definitely matters ahaha
homeworkatedog
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do we think itll align better this year than other years? i know quite a few ppl doing the test found it p hard esp w/ q14, so what do you guys reckon the e4 cutoff will be?
I doubt it will deviate far from a 55 because i would say about 8 marks from q14 would be considered band 6 and then you have the 7 for the f(x)=g(x) and then the volume of revolution.
its not?
Yes, q14a is challenging but I believe that the difficulty of this paper has been overstated a little compared to past years, given the other parts are somewhat easier (and even 14a to it's equivalent). I would expect a borderline band 5-6 student to lose around 7 marks on question 14 (either 6+1 Or 5+2) and no more than 2 marks on each of the other sections and one mark on multiple choice (Q9 most likely). So far from being extremely easy or anything, but in my opinion just a bit more approachable than past years.