• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Complex number help!! (1 Viewer)

cchan334

Member
Joined
Nov 16, 2020
Messages
29
Gender
Female
HSC
2021
I don't know why but I keep doing this question but I keep getting the same wrong answer.
The question is:
Using Euler's formula, e^(ix) = cosx + isinx, show that if z=re^(ix), then:
1/z +1/(conjugate of z) = 2cosx/r^2

For some reason, I keep getting LHS = 2cosx/r instead of 2cosx/r^2
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,401
Gender
Male
HSC
2006
When you put over a common denominator use the fact that

 

cchan334

Member
Joined
Nov 16, 2020
Messages
29
Gender
Female
HSC
2021
When you put over a common denominator use the fact that

I tried that but I got the same answer? Maybe it's something wrong with my algebra?

I get LHS = 1/z + 1/(conjugate of z)
= z+ conjugate of z/ (mod of z squared)
= 2 Re(z) /r^2
= 2rcosx / r^2
= 2cosx/r ????
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,401
Gender
Male
HSC
2006
Ah right, didn’t work it fully through in my head. I think your answer is correct.
 

YonOra

Well-Known Member
Joined
Apr 21, 2020
Messages
375
Gender
Undisclosed
HSC
2021
LaTeX, it’s embedded in this forum using [ tex ] and [ /tex ] wrapped around the code (without the spaces)
So once you click on latex and you have [ tex ] & [ /tex ] what do you do?
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,401
Gender
Male
HSC
2006
So once you click on latex and you have [ tex ] & [ /tex ] what do you do?
Put in the code for whatever you want to write up and post it. You can quote some of the posts above to see examples of what that code looks like.

There is also a guide in the stickied thread (located in the Maths forum) below (a bit outdated but most of it is still relevant)
 

YonOra

Well-Known Member
Joined
Apr 21, 2020
Messages
375
Gender
Undisclosed
HSC
2021
Put in the code for whatever you want to write up and post it. You can quote some of the posts above to see examples of what that code looks like.

There is also a guide in the stickied thread (located in the Maths forum) below (a bit outdated but most of it is still relevant)
Cool, thank you
 

CM_Tutor

Moderator
Moderator
Joined
Mar 11, 2004
Messages
2,642
Gender
Male
HSC
N/A
So once you click on latex and you have [ tex ] & [ /tex ] what do you do?
So, for example, my post (excluding the tex codes) was:

\begin{align*} \frac{1}{z} + \frac{1}{\bar{z}} &= \frac{1}{z} \times \frac{\bar{z}}{\bar{z}} + \frac{1}{\bar{z}} \times \frac{z}{z} \\ &= \frac{\bar{z} + z}{z\bar{z}} \\ &= \frac{\bar{z} + z}{|z|^2} \text{ as } z\bar{z} = |z|^2 \\ &= \frac{2\Re{(z)}}{|z|^2} \text{ as } z + \bar{z} = 2 \times \Re{(z)} \\ &= \frac{2\Re{(z)}}{r^2} \text{ given } |z| = r > 0 \\ &= \frac{2 \times r\cos{x}}{r^2} \text{ given } z = r(\cos{x} + i\sin{x}) \\ &= \frac{2\cos{x}}{r} \end{align*}

Expanding this out...

\begin{align*}
\frac{1}{z} + \frac{1}{\bar{z}} &= \frac{1}{z} \times \frac{\bar{z}}{\bar{z}} + \frac{1}{\bar{z}} \times \frac{z}{z} \\
&= \frac{\bar{z} + z}{z\bar{z}} \\
&= \frac{\bar{z} + z}{|z|^2} \text{ as } z\bar{z} = |z|^2 \\
&= \frac{2\Re{(z)}}{|z|^2} \text{ as } z + \bar{z} = 2 \times \Re{(z)} \\
&= \frac{2\Re{(z)}}{r^2} \text{ given } |z| = r > 0 \\
&= \frac{2 \times r\cos{x}}{r^2} \text{ given } z = r(\cos{x} + i\sin{x}) \\
&= \frac{2\cos{x}}{r}
\end{align*}
  • the begin and end align* causes whatever character is preceded by an & to line up, putting the equal signs above each other
  • the \frac{x}{y} gives a fraction x over y
  • the function \bar{z} displays the conjugate of z
  • note that the braces { } are paired and so you must be careful to close each one you open
  • the \\ gives a new line (not needed in the line before the \end of align*
  • the functions like \Re{(z)} and \cos{x} treat Real part and cosine as functions and displays them
  • the \text{xxx yyy} inserts "xxx yyy" as text (including the space) instead of treating it as Maths and showing xxxyyy.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top