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What's the answer?Hey, would greatly appreciate any advice on how to go about doing this question:
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I've thought about it for ages, and there simply doesn't seem to be enough information to apply the formulas I know (eg. trig) to solve this.
Thanks! I still don't really understand how to apply trig to this instance though - from my understanding, we have a triangle with side r, r + 1.7m and an unknown hypotenuse. I'm also not sure of the reasoning behind the t*2pi/26400 formula? I'm not sure if I'm misunderstanding the question or if my visualisation of the problem is all wrong.Hi, this question can be done if you account for the fact you know the rate of rotation of the earth (24 hours (86400 sec) for one revolution). Using trig we can calculate the angle this moves through where one side r and our hypotenuse is r + 1.7 m. We can then find theta which equals t * 2 pi / 86400 where t is our 11.1 seconds and from here we can work out the radius. Good luck and let me know if you would like more working to help.
Regards,
Edzion education
What's the answer?
The hypotenuse is r + 1.7 metres in length (as Edzion has already stated).Thanks! I still don't really understand how to apply trig to this instance though - from my understanding, we have a triangle with side r, r + 1.7m and an unknown hypotenuse. I'm also not sure of the reasoning behind the t*2pi/26400 formula? I'm not sure if I'm misunderstanding the question or if my visualisation of the problem is all wrong.