? =)(= Active Member Joined Jul 14, 2021 Messages 649 Gender Male HSC 2023 Oct 13, 2022 #1 part b i cant figure how to get the sum
Lith_30 o_o Joined Jun 27, 2021 Messages 158 Location somewhere Gender Male HSC 2022 Uni Grad 2025 Oct 13, 2022 #2 use the sum to product of pairs of roots to show that then use the fact that to find and the rest should be easy
use the sum to product of pairs of roots to show that then use the fact that to find and the rest should be easy
? =)(= Active Member Joined Jul 14, 2021 Messages 649 Gender Male HSC 2023 Oct 13, 2022 #3 would there be 15 pairs of prod to sum?
Lith_30 o_o Joined Jun 27, 2021 Messages 158 Location somewhere Gender Male HSC 2022 Uni Grad 2025 Oct 13, 2022 #4 =)(= said: would there be 15 pairs of prod to sum? Click to expand... yeah the roots would be lets say you start off with multiplying with and then multiplying with the product of those pairs of roots will cancel each other out when adding them to each other. so basically you get all but three terms cancelling out, which is where the root multiplies by their negative equivalent ie alternatively i think you might be able to do the question by letting
=)(= said: would there be 15 pairs of prod to sum? Click to expand... yeah the roots would be lets say you start off with multiplying with and then multiplying with the product of those pairs of roots will cancel each other out when adding them to each other. so basically you get all but three terms cancelling out, which is where the root multiplies by their negative equivalent ie alternatively i think you might be able to do the question by letting
? =)(= Active Member Joined Jul 14, 2021 Messages 649 Gender Male HSC 2023 Oct 13, 2022 #5 ohh okay i get it thanks guys