Grammar 2020 questions (1 Viewer)

[SadCeliac]

Hi all,

Could someone please explain this to me? I got A...



Thanks!

 

[HSCya1234567]

is this the SGS trial haha?

 

[SadCeliac]

is this the SGS trial haha?

nope its grammar 2020

 

[SadCeliac]

nope its grammar 2020

WAIT IS SGS GRAMMAR??? LMAO IM STUPID AS

 

[HSCya1234567]

Sorry i meant that lol I asked my teacher this let me go find what she said

 

[SadCeliac]

also this <3

 

[SadCeliac]

 

[HSCya1234567]

Ah found it, so i got quite stuck on this too, so basically adding 10ml of solvent x dilutes the concentration of I2 in the solution. So to increase the Concentration again, the Eq shifts to favour the forward reaction, decreasing the conc of I2 in Y

 

[SadCeliac]

Ah found it, so i got quite stuck on this too, so basically adding 10ml of solvent x dilutes the concentration of I2 in the solution. So to increase the Concentration again, the Eq shifts to favour the forward reaction, decreasing the conc of I2 in Y

ohhhh okay that makes sense - thanks

 

[HSCya1234567]

View attachment 39178

Is there a lone pair at 3 by any chance?

 

[SadCeliac]

Is there a lone pair at 3 by any chance?

I didn't think so, because if you look at the number of bonds to the C, it has four (the C=O, CH-C, C-OH).

 

[HSCya1234567]

View attachment 39177
also this <3

Sorry it's been a while since I did this paper lol, I *THINK* This is because NaOH produces 1 hydroxide ion when dissolved in water and Ba(OH)2 produces 2 so they just add up

 

[HSCya1234567]

I didn't think so, because if you look at the number of bonds to the C, it has four (the C=O, CH-C, C-OH).

so true


amines and amides aren't in our paper for some reason so ive just been skipping any questions with them in it

 

[SadCeliac]

Sorry it's been a while since I did this paper lol, I *THINK* This is because NaOH produces 1 hydroxide ion when dissolved in water and Ba(OH)2 produces 2 so they just add up

Yeah so I said Ba(OH)2 + NaOH --> Na+ + Ba2+ + 3(OH-) --but had no clue what to do from there

 

[HSCya1234567]

Yeah so I said Ba(OH)2 + NaOH --> Na+ + Ba2+ + 3(OH-) --but had no clue what to do from there

I think it wouldn't add up to 3(OH) per say but just the total concentration of OH ions in the solution if that makes sense

 

[SadCeliac]

I think it wouldn't add up to 3(OH) per say but just the total concentration of OH ions in the solution if that makes sense

hmm no I still don't really get it: I have 1:1:3 of Ba:Na:OH, don't I?

 

[HSCya1234567]

well yes, but the question is asking for the "concentrations of each of the ions in the solutions formed" so its not asking for the ratio but the final conc?

 

[SadCeliac]

well yes, but the question is asking for the "concentrations of each of the ions in the solutions formed" so its not asking for the ratio but the final conc?

still don't get it :/ sorry

 

[SadCeliac]

alsooo is hydration of alkene to alcohol with conc or dilute H2SO4??

 

[HSCya1234567]

still don't get it :/ sorry

no you're good dw, if you let me think on how to better explain it i might get back to you tn, unfortunately i do have to cram the mod 8 ions flowchart into my head and cry about ext 2 maths

alsooo is hydration of alkene to alcohol with conc or dilute H2SO4??

also i'm def sure its dilute