SB257426
Very Important User
i dont think so.... last years adv was super easy while we all know about last years ex2Question
Is there a correlation between 2u/4u/3u difficult of papers? As in 2022 hard for all, 2020 easy for all etc.
i dont think so.... last years adv was super easy while we all know about last years ex2Question
Is there a correlation between 2u/4u/3u difficult of papers? As in 2022 hard for all, 2020 easy for all etc.
and follow up - that's always the case for finding complex roots?View attachment 40590
guys just checking because i had a mindblank looking at this solution...
line two should have e^ipi + 2kpi - yes??
wdym dependant on z^n???dependant on what the root is of! but yeah that same notion
Look I'm not entirely sure but pretty confident that 4U and 3U papers are written by the same people, and all of the 2U papers are written by the same people, but those two groups are distinct. i.e today's 4U may hint at the level of 3U, but 2U probably won't tell us anything.Question
Is there a correlation between 2u/4u/3u difficult of papers? As in 2022 hard for all, 2020 easy for all etc.
oh no sorry; had meant moreso if it were z^5-1 in the original eq'n – but you would've known that hahawdym dependant on z^n???
are you saying I do a different + kpi for (e.g.) z^6 = 1
yesView attachment 40590
guys just checking because i had a mindblank looking at this solution...
line two should have e^ipi + 2kpi - yes??
most of the time they are gonna tell u to solve z^n = 1 or -1 so that would be the case yes but ofcourse if they ask u to solve z^n=4+4i or something then you would have to find principle arugment and add 2kpiand follow up - that's always the case for finding complex roots?
bruh, not me picking AView attachment 40591
hey guys im just a bit confused for this one question
the question is resistance to square of velocity but i dont understand how they break it down??
And when they break it down the question basically becomes a resistance proportional to velocity question? like i dont understand why and how they get rid of the square in the question then turn it into just resistance proportional to velocity.
because the vector for velocity is next to it, so it makes it kv^2View attachment 40591
hey guys im just a bit confused for this one question
the question is resistance to square of velocity but i dont understand how they break it down??
And when they break it down the question basically becomes a resistance proportional to velocity question? like i dont understand why and how they get rid of the square in the question then turn it into just resistance proportional to velocity.
you really need to look at the magnitude of the resistance vector in option D, and when u find its magnitude u get resistance = kv^3, and so u can immediately rule that out.Obviously not A and D as we are adding the resistive force which makes no sense at all.View attachment 40591
hey guys im just a bit confused for this one question
the question is resistance to square of velocity but i dont understand how they break it down??
And when they break it down the question basically becomes a resistance proportional to velocity question? like i dont understand why and how they get rid of the square in the question then turn it into just resistance proportional to velocity.
wham bam here comes pam omd
ahhh should’ve said sam, missed opportunitywham bam here comes pam omd
i had that for english so it's a good omen surelyguys I had a dream where the exam was really easy maybe this is a sign