Chemistry Predictions/Thoughts (1 Viewer)

[Life'sHard]

Just because you found it easier doesn't reflect the rest of the student population.

Skill diff

 

[jc7726]

that test was so much nicer than i expected. i was thinking i was gonna get screwed over and maybe a raw 70 but if everything goes right i might get 90+

 

[year10studentpreparin]

that’s fair ig, from talking to friends most found it easier but a lot of us are better with quantitative stuff so it might not be super representative of everyone

I think its more that my mx2 mates study a lot more because thats expected of them and why they can do mx2 because of studying a lot rather than an advanced mate of mine who just plays video games all days and gets crap plus he fails advanced too

 

[Aminza21]

what we getting for q 19 and 20 mc

 

[carrotsss]

what we getting for q 19 and 20 mc

if im remembering the questions correctly, B and D

 

[qldbulls]

No one by any chance got a tertiary alcohol for Q36?… . Spectroscopy question.

Tertiary can't oxidise into C

 

[Xyzpt]

Tertiary can't oxidise into C
[/QUOT


I just left it as a tertiary alcohol for C

 

[dumNerd]

Can somebody send the paper

 

[sid_05]

seems like a lot of us finished today on chem lol,
feels like nobody here does physics???

I do!!!!

 

[Adrian_jnader]

Did anyone upload solutions??

 

[tywebb]

Can somebody send the paper

See post #253 for paper

 

[jc7726]

i don't know if they're talking abt something completely different, but you might have been able to use concentrations to find how much was added instead. since [CO2] = [CO] let [CO2] = x
x/x^2 = 10
x = 10x^2
1=10x
x = 0.1 for the conc of both

 

[jc7726]

how? I was trying to solve for 2 terms, (x being the change in equilibrium, y being the how much co2 was added). They said they were equal so keq = 1/x, I got this equation in the end.View attachment 41177 didnt want to waste my last 20 mins trying to solve so i cut my losses. I still cant solve it lol.

sorry meant to reply, ^

 

[Retrodawn]

but didnt you have to find the amount of co2 added or something

 

[dumNerd]

Why was there no non basic theory what so ever in this exam bruh.

I mean I think chem should be this way but unfortunate for people who don’t have calculations as their strong suits

 

[=)(=]

i don't know if they're talking abt something completely different, but you might have been able to use concentrations to find how much was added instead. since [CO2] = [CO] let [CO2] = x
x/x^2 = 10
x = 10x^2
1=10x
x = 0.1 for the conc of both

pretty sure i got 0.169 added

 

[=)(=]

Why was there no non basic theory what so ever in this exam bruh.

wasnt last yr the same tho and every year prior

 

[dumNerd]

wasnt last yr the same tho and every year prior

Not really 2021 there was the ph buffer theory based q and a bunch of q which involved theory and calc understanding together

2022 was more calc but there was still relatively hard theory based q e.g. last q and the 9 mark was a theory q (although not difficult hard to interpret what they really wanted, was a long q if you thought they wanted method)

2023 has even more calc

 

[Jane Mao]

Can someone confirm what they got for Compound C? It was hexan-3-one right??!

 

[carrotsss]

Can someone confirm what they got for Compound C? It was hexan-3-one right??!

yep it was