hi guys pls help again (1 Viewer)

[Sylfiphy]

this one is pretty easy but im not getting the right answer

differentiate x+y / x-y with respect to X

 

[Average Boreduser]

this one is pretty easy but im not getting the right answer

differentiate x+y / y-x with respect to X

quotient. rule and implicitly diff.

alternatively, you could split the numerator and diff that way ig.

 

[Sylfiphy]

quotient. rule and implicitly diff.

What is my issue here? (The answer I got is obviously wrong btw)

 

[Average Boreduser]

What is my issue here? (The answer I got is obviously wrong btw)

Recall they want to diff with respect to x. you can't just diff y as if it's just in terms of x.

 

[liamkk112]

this one is pretty easy but im not getting the right answer

differentiate x+y / y-x with respect to X

u need to use chain rule:

 

[Sylfiphy]

Recall they want to diff with respect to x. you can't just diff y as if it's just in terms of x.

don't they just become constants ..? so zero

 

[Average Boreduser]

don't they just become constants ..? so zero

no definately not. y is a variable in the qn not a constant

if it was a constant, they would tell you. i.e. somehting like 'where y is a constant'

 

[liamkk112]

don't they just become constants ..? so zero

nope. i think you are getting confused with partial derivatives, whole different thing

 

[ExtremelyBoredUser]

to make it very simple, always consider y as y(x) for the hsc when they asking you differentiate (haven't read q just inferring from above).

 

[Sylfiphy]

nope. i think you are getting confused with partial derivatives, whole different thing

I swear I can’t find what I’m doing wrong

 

[Average Boreduser]

I swear I can’t find what I’m doing wrong

you're not diffing y for some reason

 

[Average Boreduser]

Analyse it carefully. THere's a y', no they did not make a typo. if there is a y', then there is most definately going to be some application of implicit differentiation here.

 

[Sylfiphy]

Analyse it carefully. THere's a y', no they did not make a typo. if there is a y', then there is most definately going to be some application of implicit differentiation here.

ong that's what im doing also what do u mean im not differentiating y cuz the term is one thing right?

 

[Average Boreduser]

ong that's what im doing also what do u mean im not differentiating y cuz the term is one thing right?

use chain rule if it's not in terms of x. You can't assume it's a constant.

 

[Average Boreduser]

ong that's what im doing also what do u mean im not differentiating y cuz the term is one thing right?

 

[Average Boreduser]

View attachment 43193

i.e. differentiate y in terms of x:
dy/dy*dy/dx=dy/dx=y'.

 

[Sylfiphy]

View attachment 43193

bro I would've never done this for my working I was so off wtf..

 

[liamkk112]

bro I would've never done this for my working I was so off wtf..

just remember this