• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad
jnney

jnney

lemon
Joined
Last seen
Messages
1,437
Reaction score
20
Points
38

Profile posts Latest activity Postings About

  • S
    I am in no position to give advice to this matter, but if I were you, I would wait until the holidays and see if I could claw my way back so that I am aligned with the rest of the state.
    S
    Prehaps, you best seek the advice from your peers. But ultimately, it's your own decision. Only you know what is best for yourself. Make a wise choice little one...
    J
    Hey Jenny! Can you call me at 0423 768 088, email me at jaysonj123@hotmail.com or give me your mobile number to call you? We can discuss tuition further =)
    Bored_of_HSC
    Meh as long as you're really really confident with your other subs, i'd say go for it. But still just wait. Don't be hasty.
    Bored_of_HSC
    Why?!?!?! Just keep it till the end of term 1 imo. Always good to have a backup.
    Or post a thread. There's a thread for everything on here anyway :p
    S
    thanks for offering your advice, its really kind of you but unfortunately I dont go to high school anymore I just graduated
    4025808
    LOLOLOLOLOLOL hopefully :)

    yeah you have fun studying for term 1 assessment tasks too :p
    4025808
    fark. but don't worry too much. Try the best you can, and use the resources as much as possible from this site :)
    I kinda felt that way at the beginning of year 12 as well, but then in term 1, people starting losing steam, and then I took over. But then in term 2 and up until the trial, I lost motivation.
    lydia1992
    hahahhahah my brain is thick i've tried to do it 3 times and at the end i gave up so i went asking everyone and finally someone solved it ^_^
    lydia1992
    You'll find the gradient = -4/3

    Then point gradient formula, you'll get 4x + 3y - 9 = 0

    Sub y = x^2/12

    4x + x^2/4 - 9 = 0
    x^2 + 16x - 36 = 0
    (x + 18)(x - 2) = 0
    Therefore x = 2 or -18

    Since you already know the point which corresponds to x = 2, sub x = -18 in x^2 = 12y
    y = (18)^2/12
    = 27
    So you have (2, 1/3), (-18, 27)

    Use the distance formula and you end up with:
    100/3 or 33.3 units.

    a guy called nightweaver066 told me
    S
    I am not creepy. SpiralFlex is mis-understood. I have offered my services to humans. They still hurt Spiral.
  • Loading…
  • Loading…
  • Loading…
Top