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Sure fair enough but that was just an extreme example - I don't actually need a zero velocity for the argument to work. For instance, I could assume that she opens the parachute when she is falling downard at 0.01 m/s (i.e. something definitely below the terminal velocity). In that case, the...

I don't think this is true in general. Suppose that they opened the parachute immediately when they jump (i.e. at zero downward velocity). Therefore in spite of the parachute being opened, their downward speed will still continue to increase because their weight force exceeds air resistance.

I agree with someth1ng. I assumed in my response that when the question stated "terminal velocity" , it was the "terminal velocity" of the person + the parachute.

I think the answer should be C (no change in frequency, speed decreases) The frequency of any wave never changes when it moves into a different medium. This is because the frequency is dependent only on the source of the wave. Another way of seeing this is that if the photon frequency changes...

I think the answer should be B (downward acceleration, downward speed) - please see my reasoning below (apologies for the lengthy explanation, but I think this question is a bit subtle / confusing so I spelled out my reasoning in detail). EDIT: Note that this explanation assumes that "terminal...

It doesnt. W and Z bosons mediate the weak force. The strong force is mediated by gluons.

You can think about it iteratively. Supposed you had a weak base called "B-" which accepts a proton in this equilibrium. HB <-> B- + H+ Now what happens if you add an acid (i.e. HA) to the solution from a strong acid? Then whatever B- is availabile will accept the H+ and form HB to oppose...

The question is wrong and doesn't make sense. sin-1(x) + cos-1(x) = pi/2 for all -1<=x<=+1. So it only makes sense for the case k = pi/2, and x can be anything in the domain of sin-1 & cos-1. (You can see that the LHS is constant by differentiating LHS and seeing that it equals zero.)

There is no direct relationship between the two - we also need to know the frequency of incident light. KE = hf - W \\ qV_s = hf - W \\ V_s = \frac{hf-W}{q} where V_s = stopping voltage, f = frequency, W = work function, q = electron charge.

At the top of the loop, there are two forces acting on the object: F_{Normal}, mg. The required centripetal force also points downward. Therefore F_{c} = F_{Normal} + mg \implies F_{c} - mg = F_{Normal} Note that we must have F_c - mg > 0 , otherwise the object is moving too slowly to...

I don't think this it is a meaningful question to ask how the two can be differentiated because in practice, when you look at absorption or emission spectrum it will be broadened due to multiple factors at the same time (i.e. the pressure broadening is layered on top of doppler broadening). You...

Another better way of figuring this out rather than to try use Lenz's Law is to imagine a test positive charge sitting on the metal disk and apply the Lorentz force law (F=qvB or F = IBL). The test positive charge is moving to the left when the disk rotates into the magnetic field (so I, the...

Doppler broadening is driven by the fact that the source of light is moving towards (blue shifting) or away (red shifting) from the observer. This can be due to random thermal motion or in the context of stellar spectra, the rotation of the source (i.e. if the star is rotating, one half rotates...

The equation for centripetal accelaration is a kinematic one. It is a bit algebraically involved, so I'll point you to two sources 1. http://hyperphysics.phy-astr.gsu.edu/hbase/cf.html 2. https://physics.info/centripetal/ Note that since accelaration is a vector, there are two things that need...

Just a warning: UNSW Physics is very good in first year, but it is trash from 2nd year onwards (labs are hell as well). You will have to learn it yourself from websites like Mit opencourseware. UNSW completely ruined physics for me. So make sure you keep your comp sci degree as a back up...

The left hand side is the average of (m+1) numbers {a^0,a^1,a^2,...,a^(m)} and the right hand side is the average of m numbers {a^0,...,a^(m-1)}. Since a^m is bigger than all the other numbers, having that present will increase the average. You can instead prove that adding a number greater...

I got the same scores as you and didn't receive an offer from Uni of Adelaide (I got an email from the actual uni itself saying I did not rank high enough). I didn't get an offer to Flinders Uni either, which doesn't even have an interview. :/ edit: im from NSW so i was an interstate applicant

What the universities usually look at is your performance in your undergrad degree as well as GAMSAT. So I think you'd be better off doing whatever interests you (even if its an arts degree) and therefore, you will get a higher grade point average in. The only thing I've taken into consideration...

I know this thread is 1 month old, but for the sake of anyone reading this later on down the road the allowable angle of re-entry varies depending on the design of the space shuttle and how its going to enter (eg. ballistic re-entry with no retrofired thurst engines, or space shuttle that does...

As a rough indicator of cut-off criteria for NSW Unis: UNSW - median atar for entry ~99.6, umat required usually 90+%ile for interview offer. In order to be competitive you need 99+ Griffith provisional entry - 99.6+ atar (not nsw but you can still apply through uac for it) USYD Combined-...