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bump, can someone please answer my questions

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What's the difference between R and R+?

What do you mean? Would the domain of f(g(x)) just be the domain of g(x), which in this case is restricted to (-infinity,-3]?

So in what cass is the square root both the +ve and -ve and in what cases is it only the +ve? Also can someone please help me with the below questions? 2sin(2x-pi/6) = 1 for a domain of -pi<x<pi we multiply the domain values of 2, so it becomes -2pi<2x<2pi but then do we subtract the...

if we had to find the derivative of sqrt(x^2+3), and evaluate it when x = 1, we get 1/(sqrt(4)), which so in this case, would it be 1/2 and 1/-2? or just 1/2?

are my questions even showing up in the forum?

f(x) = sqrt(x+1), and has a restricted domain of [0, infinity) g(x) = x^2+4x+3, and has a restricted domain of (-infinity, -3] How would i find the range of f(g(x)) without a calculator? f(g(x)) = sqrt(x^2+4x+4), so would I use the domain of g(x) as the domain of f(g(x))?

thought i'd start a new maths questions thread 2sin(2x-pi/6) = 1 for a domain of -pi<x<pi we multiply the domain values of 2, so it becomes -2pi<2x<2pi but then do we subtract the domain values by -pi/6 or since 2sin(2x-pi/6) = 2sin(2(x-pi/12)), do we subtract the domain values by -pi/12...

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2sin(2x-pi/6) = 1 for a domain of -pi<x<pi we multiply the domain values of 2, so it becomes -2pi<2x<2pi but then do we subtract the domain values by -pi/6 or since 2sin(2x-pi/6) = 2sin(2(x-pi/12)), do we subtract the domain values by -pi/12? Thanks

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bump please

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can someone please answer my questions?

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Is this always the case that you only take the +ve?

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