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How long has it been? Hi.

Re: MX2 2016 Integration Marathon Hey guys not an integration Q but there will be an integration bee @ O'week UNSW. Feel free to rock up. Macauley Theatre (QUAD 1027) Thurs 25th Feb 2016 at 11am.

\\{\color{Red} 1.} \;$Notice that they kindly gave us$\; \pi \; $is approximately$\; 3 \;+ \;$(some fraction less than one). That is,$ \pi \approx 3 + \frac{1}{a_{1}}. \\$To solve for$\; a_{1}\; $we simply subtract 3 from both sides and take the reciprocal.$. \pi - 3 = \frac{1}{a_{1}} a_{1}...

Love how this thread instantly jumps to one conclusion without asking the OP what course he/she is planning to do.

Look for your university's academic calendar. For example: https://student.unsw.edu.au/calendar

Yes you can do this with Adv Math/Comp Sci or Sci/Comp Sci.

4 GB?! I dont remember our generation having those.

Raspberry Pi are better than those bombs (at least the ones I had when I was in high school)

Re: Confessions Black guy always wins huehue

Re: Confessions fed express

SCG Thursday Night The peaceful place in the city with all the fishies. Something garden. The little peaceful park near Darling Harbor.

Re: HSC 2015 4U Marathon - Advanced Level Yes I will fix it give me a moment.

Re: HSC 2015 4U Marathon - Advanced Level \textup{Or simply derive the inequality from AM-GM that is useful. Possibly one involving squares,} a^2+b^2+c^2 \geq ab+bc+ca \textup{So,}\;a^2+b^2+c^2 = (a+b+c)^2 - 2(ab+bc+ca) \geq (a+b+c)^2 - 2(a^2+b^2+c^2) (a+b+c)^2 \leq...

Re: HSC 2015 4U Marathon - Advanced Level Nesbitt's inequality is nice. \textup{Observe that,} (\frac{a+b}{b+c} + \frac{b+c}{a+b})+ (\frac{b+c}{a+c} + \frac{a+c}{b+c})+ (\frac{c+a}{a+b} + \frac{a+b}{a+c}) \geq 2 + 2+ 2 \textup{Group each of the same denominators,} (\frac{a+b}{b+c} +...

^With conditions

Life is Strange Get it.

Starting watching Ore monogatari.

^^ excellent work simmy.

Re: HSC 2015 3U Marathon Yes

Re: HSC 2015 3U Marathon Yes that's the form I was looking for