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It is a bit difficult to explain, but I'll try. You basically draw a cross (X) and on the LHS (end points) you find two values that multiply together to get 4x^2. This could be 4x and x or 2x and 2x. On the RHS (end points) you need two values that multiply to get 15y^2 which could be 5y and 3y...

1) 4x^2+17xy+15y^2 Using cross method, you get (4x+5y)(x+3y) 2) 5a^3b(3a-2ab-4b^2)?