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that is only worth one mark, you need to elaborate more

dubious

^

eh; no, I doubt Trebla will go that way. Also nobody in the exam brought it up, so they must have made the implicit assumption as well we're not that pedantic about the marking system so don't expect us to be like "oh this q was flawed free marks"

Thanks for pointing this out. I have changed the files for both posts accordingly. I pray this is the last mistake/technical gap we have *sighs heavily*

I have reuploaded the file (into the post) since this was posted, as it was noticed that the slice diagram for the volumes question was missing (I accidentally commented out the line of code for that image, my bad) Here are the files anyway to avoid confusion.

Thank you to everyone who showed up! I'm sorry for the typos (although nobody noticed that Trebla wrote "focii" instead of "foci" Here are the papers, edited and refined (and a little bit of visual changes as well to both)

I don't believe it has a solution contained within MX2. But feel free to take that as a challenge.

why is it called king's property anyway border reflection (or border flip) is the most logical choice of name regal name has no connection whatsoever

Just do an enormous computational bash in NumPy :dab:

That... doesn't necessarily have to be true, but my intuition agrees with that. Formally, however, I do not.

intuition said it was φ-like but i didn't want to stay up that late to figure it out; a good one nonetheless

These are all beyond the scope of the syllabus.

*laughs in measure theory*

Re: HSC 2018 MX2 Integration Marathon This only works for x>0 because the resultant primitive does not have a derivative at 0, yet the function to be integrated is clearly defined at 0.

Re: HSC 2018 MX2 Integration Marathon There is a mathematical algorithms paper exploring the construction of an algorithm that can find the continuous primitive of these example periodic functions which are typically done using substitutions that result in countable discontinuities.

Re: HSC 2018 MX2 Integration Marathon That's correct, but you don't need to graph the function, you just need to know the sign of the thing under the absolutes at every point in the region.

Re: HSC 2018 MX2 Integration Marathon *soluble

Re: HSC 2018 MX2 Marathon tsk tsk trying to introduce multivariable optimisation in a sidestepping manner

Re: HSC 2018 MX2 Integration Marathon Continuing on from the simplification \int_0^\frac{\pi}{4} \frac{2\tan{x}}{\sqrt{2+\cos{2x}}}\text{d}x = \int_0^\frac{\pi}{4} \frac{2\sin{2x}}{(1+\cos{2x} )\sqrt{2+\cos{2x}}}\text{d}x Reverse the chain rule twice to obtain: \int_0^\frac{\pi}{4}...