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Wat raw mark would correlate to state ranking?

Wat raw mark would correlate to state ranking?

Really? It was ok

Expecting95-99 raw so easy

Me too:)

Adv English Chem Physics Mathematics Extension 1&2 (2013 hsc, so finishing them in 2 days)

Hi, I am currently looking for a tutor to prepare me for interviews/career guidance, could you PM me if you re interested?

Hi, I am currently looking for a tutor to prepare me for interviews/career guidance, could you PM me if you re interested?

i) 42C9 ii) 42C9 !!!!

UNSW or Usyd? (pls post your reasons) Which one of these courses would be better? UNSW - quantitative risk Usyd - financial maths

Try Terry Lee Advanced Mathematics They have detailed worked out solutions and also checkpoints

i agree I assumed that the area bounded by the curve and the x axis and x=0 and8 is rotated around y axis

1. Draw y=1/sqrt (x) on a number plane 2. Put integer numbers 1, 2, 3, ... 100 3. Draw rectangles on each interval with 1 unit space, and each rectangles should be above the curve , ( bad explanation...) 4. Note that sum of all rectangles equals to 1/sqrt(1) + 1/sqrt(2) + ... + 1/sqrt(100) 5...

I think I figured out the answer for the first one Btw got 1864/15 pi cubic unit

Yes but you will be fine if you study fitzy 2unit because it covers yr11 & 12, then do 3unit fitzy You can use Cambridge for harder concepts Ps Yr11 foundation is very important

I agree Spend 5 months to finish all concepts ( use Cambridge or Fitzy to get the basic and use Terry Lee for better understanding) 2hours a day By this time you would have mastered 4 u 50% Start doing trials and hsc ( 2 a week normally , 5 a week during holidays) Then you would have mastered 100%

You're not wrong!! Just my typo ii) - silly mistake

Yeab I did 2nd one wrong I did×8 not7 silly... The fourth I did my one by (S,_, J) , 5people - 2! For S and J can swap, 6 groups hence6! 1 for B (S,_,_, J), 4people - 2! For S and J can swap, 5groups hence 5!, 2 places for B and put one of 5 into one 5p1 (S,_,_,_J), 3people - etc (S,_,_,_,_J) 2...

I'll just post the answers i) 2×4!× 4! ii) 4!× 4! iii) 8!-2! 7!-2! 6! 6= 21600 iv) 6!× 2! + 5P1×5!× 2! + 5P2×2! 4! 3 + 5P3×2! 3! 4 + 5P4 ×2! 2! 5 + 5P5×2!× 6×1! = 12240

3 x = 2costheta - cos2theta in this equation put x = 1 and let cos theata be u then using compound angle u(u-1) = 0 solving it cosA = 0 or cos A= 1 A = 0, pi/2, 3pi/2, or 2pi hence y = 0, 2 , -2, 0 hence coordinates are (1,0) and (1, 2) (1, -2) is rejected