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What I wrote was wrong because my initial assumption was incorrect. We must regard the same letters as identical. You only need to worry about outcomes when doing probability. Although don't worry about this for high school.

Sorry would you be able to elaborate, like specifically how the cases from 100p5 collapse to 5!?

Dw I actually got it this time. Here's the next question I've done a,b and some of c but I'm struggling to show the cases are equally likely. any hints?

Edit: I was wrong xD Hey here's the rest of the q and I managed to do b) but my expression with c inst quite working. I get \frac{1}{3^{n-1}}[^{n+2}C_{3}+^{n+5}C_{6}+...+^{2n-1}C_{n+1}][1-^{n}C_{1}+^{n}C_{2}-...+^{n}C_{n}] Although I know I should be able to show the answer is...

Ok cool thanks for that. I managed to do the rest of the q, thanks heaps

Hey need some help with questions. Here's the 1st one. Edit I'd like a hint not the answer. Thanks heaps

You can receive informal offers (i.e. not directly via UAC) by email or text. I got a unsw and wsu ones by email. Note it often goes to your spam, so make sure you check!

it is a nightmare for a restaurant, its so fkn annoying

I really wanted to do space engineering/adv math at sydney but I didnt do as well in my finals as I hoped. However I got an early offer into combined actuarial studies at unsw which I would never accept due to personal reasons, but it definately made me consider actuarial studies. I ended up...

Yeah thanks heaps. I've done a lot of binomial stuff this semester in another unit, it just wasnt making sense. But just to clarify you can either do the general computation for tayler/macluaran series or you can fiddle with a function until it reduces a well-known result? Thanks for your help :)

So you can just the sum be J or whatever. J=\sum_{n=0}^{\infty} \frac{x^{n}}{n}\\ {J}^{\prime}=\sum_{n=1}^{\infty} x^{n-1}\\ J^{\prime}\\ \text{This is effectively the normal geom series now which you show by subbing another variable. So}\\ J^{\prime}=\frac{1}{1-x}\\ \int J^{\prime} = \int...

Why is it -log(1-z)?

Hey would anyone be able to help me with these 2 q's: For this one I don't know how to do the series with 1/n For this one I just dont understand the binomial form in general. Oops find the tayler series for it Any help would be greatly appreciated!

Start of by stating, we regard the letters as distinguishable. If it were probability then you would say, to produce equally likely outcomes. But this is beyond the level at school. So we have 1W,8O,3L,1M, such that all the O's,L's are different. You can introduce subscript etc. i) If no O's...

They dont explain that well in highschool. Because if you were asked to find the probability of one of the examples above you would need to regard the letters as distinguishable to produce equally likely outcomes, which you have inadvertently done. Sometimes it is valid to view the given letters...

I wanted to do actuarial without moving out of home. So unsw was off the tables. Mq is a 2 hour drive so it works

Nah i go to mq because it's convenient

Guys Im so cut. I was hoping to change my degree because I'm finding finance boring. I was hoping to change to eco, but I d have to do that as a concurrent degree and I wouldnt be able to do all my exemptions for actuarial so it defeats the point. Then I can't do any of the other doubles because...

well since it says chosen we are only interested in the total combinations not the arrangements of the words

You've missed some cases and arrangements. These letter ones are generally easier to do with perms I find