Find the area bounded by the curve y=sqrt(4-x^2), the x-axis and the y-axis in the first quadrant
Could some one plz do this through integration
i set limits 2 and 0, but it gives me like 5.3333
Please help
Make sure ur calc is in RAD mode
L=r x theta
theta = ((pi)/5)/r
Sub into area of a sector formula
and rearrange to find r
then sub r in any of the formule to give theta
Tan(theta) + sec(theta)= (1-t^2+2t)/(1-t^2) + (1+t^2)/(1-t^2)
in ur line here ^ in 1st bracket, where did u get 1-t^2 from ?? Tan(theta) is =(2t)/(1-t^2)