Re: HSC 2016 2U Marathon
Ceebs posting full working this late, hopefully this is right:
$Let$\quad a=\frac { x }{ y } ,\quad b=\frac { y }{ z } ,\quad c=\frac { z }{ x } \\ $Using\quad identity$\quad { a }^{ 3 }+{ b }^{ 3 }+{ c }^{ 3 }={ (a+b+c) }^{ 3 }+3(a+b+c)(ab+ac+bc)-3abc,\\ \frac { { x...