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If you're using a drawing tablet then something simple like Windows 10's Whiteboard should be fine.

(Drawing) tablet.

You can get up to 5 points with "HSC Plus", but there are other ways to get more points.

The reason that the negation of "if A then B" is "A and not B" is because of the following. "If A then B" is logically equivalent to "not A or B", i.e. "either A is not true or B is true". (You can prove this with a truth table or just reason it out.) In particular, the latter form is not an...

1521 focuses a lot on how computers actually work, on a low level scale. If you aren't experienced with computers in general, it will probably be a bit challenging, but it shouldn't be too hard. 2521 is fairly simple. It starts out by filling a bunch of holes that 1511 left open, and the...

Rewriting (and using \sin 2x = 2 \sin x \cos x), we have ( 3 \sin \theta - 4 \sin^3\theta) + 2 \sin \theta \cos \theta = \sin \theta or \sin \theta (3 - 4 \sin^2\theta + 2\cos \theta - 1) = 0. Use the Pythagorean identity to rewrite \sin^2 in terms of \cos^2 : (2 \sin \theta) (2 \cos...

The principle of duality in the real projective plane is quite a beautiful result. It's a stunning example of how \mathbb RP^2 "removes the imperfections" from \mathbb R^2 . (To put it informally, the real projective plane is the union of \mathbb R^2 and a "line at infinity", with the...

1. You should have z^3 = -1 \pm i. Convert to polar form: z^3 = \sqrt 2 \exp\left(\pm {3\pi}/{4}\cdot i\right). Consider the case z^3 = \sqrt 2 \exp\left( {3\pi}/{4}\cdot i\right). Let z = r \exp (i\theta) so that r^3 \exp(i3\theta)= \sqrt 2 \exp\left( \frac{3\pi}{4}i\right). We get...

Your second acceleration formula doesn't actually give the correct instantaneous acceleration - rather, an approximation of it. Consider a more extreme case: After the mass leaves point A , it will again return to A (after 0.2 seconds have passed). The vector for change in velocity here...

Can you give an example? One possible reason may be that the formula you're using has implicit assumptions (e.g. uniform circular motion).

Here's a different style of proof with less algebraic manipulation. You should know what the Fundamental Theorem of Algebra is, from the Polynomials topic. To recap, the FTA essentially states that every (non-constant) complex polynomial has at least one root (in \mathbb C ). So let z \in...

Because your velocity is given in terms of x , not t . The equation is a = \frac{dv}{dt}, so if your v is not in terms of t , you can't just differentiate in that way.

My school was in the top 10.

Study as much as you need to understand the content. There’s no “right” amount, everyone learns differently. Personally, my only study was doing problem exercises and past papers.

You'll never know if you don't try. Go for it, and if things really get awful you can just drop it and you'll end up with improved skills for 2U and 3U. If you enjoy the content then the 4U workload will seem way less compared to a subject you don't like as much. Tutoring only reinforces the...

You need to learn the TeX typesetting system: https://en.wikipedia.org/wiki/TeX. In the forums you can use tex tags to properly typeset math symbols, e.g. I = \int_0^\infty e^{-x^2} \, dx. gives this: I = \int_0^\infty e^{-x^2} \, dx.

No, DM me - I'll pay $100 for it!

It's been a while since I've done this sort of thing, but I don't believe \theta is 37^\circ. 37^\circ should be the angle between the east pointing line from Bourke and the line joining the two towns. Then, \theta should be the complement of that, i.e. 90^\circ - 37^\circ = 53 ^\circ.

Usually the side p on a triangle \triangle PQR refers to the side opposite the point P .

Have you tried writing the last one in terms of the hyperbolic functions?